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请用C语言在32位环境下,两个无符号长整数相加的函数,相加之和不能存储在64位变量中

2013年11月26日 ⁄ 综合 ⁄ 共 766字 ⁄ 字号 评论关闭

#include <stdlib.h>
#include <stdio.h>

void add64(unsigned int add1,unsigned int add2,unsigned int *pSumHigh,unsigned int *pSumLow)
{
  *pSumLow = add1 + add2;
  if(*pSumLow < add1 || *pSumHigh < add2)
  {
    *pSumHigh = 1;
  }
  else
  {
    *pSumHigh = 0;
  }
  printf("h is 0x%x l is 0x%x\n",*pSumHigh,*pSumLow);
}

int main()
{
  unsigned h,l;
  add64(0xffffff00, 0x000000ff,&h,&l);
  printf("h is 0x%x l is 0x%x\n",h,l);
  add64(0xffffffff, 0x00000001,&h,&l);
  printf("h is 0x%x l is 0x%x\n",h,l);
  add64(0xffffff00, 0x000002ff,&h,&l);
  printf("h is 0x%x l is 0x%x\n",h,l);
  add64(0x00000001, 0x00000001,&h,&l);
  printf("h is 0x%x l is 0x%x\n",h,l);
  return 0;
}

运行结果:root@quieter:~# ./a.out
h is 0x0 l is 0xffffffff
h is 0x0 l is 0xffffffff
h is 0x1 l is 0x0
h is 0x1 l is 0x0
h is 0x1 l is 0x1ff
h is 0x1 l is 0x1ff
h is 0x0 l is 0x2
h is 0x0 l is 0x2


转自:http://blog.csdn.net/ysdaniel/article/details/6774329

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