在项目中有些特殊情况,得需要List里面的数据,但这个List比较特殊,得到后其元素就是一个类似Map的集合。比如List输出的数据结构如下:
[{cn=Tom, o=company, ou=Sales Department}, {cn=Lily, o=company, ou=HR Department}, {cn=jack, o=company, ou=Financial,product Department}]
这个时候需要我们把cn,ou,o对应的值取出来;一般地容易想到的是遍历List,然后对每个元素以“,”号分割后再以“=”分割取出数据,这样做效率就不高了,而且当数据存在形如:ou=Financial,product Department 的时候就会出现bug,即分割数据有误,那该怎么办呢,办法还是有的,请各位童鞋看下面的做法,为了方便看直接上code了。
public static void main(String[] args) { Map oneMap=new TreeMap(); Map twoMap=new TreeMap(); Map threeMap=new TreeMap(); List list=new ArrayList(); oneMap.put("cn", "Tom"); oneMap.put("ou", "Sales Department"); oneMap.put("o", "company"); twoMap.put("cn", "Lily"); twoMap.put("ou", "HR Department"); twoMap.put("o", "company"); threeMap.put("cn", "jack"); threeMap.put("ou", "Financial,product Department"); threeMap.put("o", "company"); list.add(oneMap); list.add(twoMap); list.add(threeMap); System.out.println("原始list:"+list); Iterator it = list.iterator(); while(it.hasNext()) { Map liMap = (Map) it.next(); System.out.println("cn:"+liMap.get("cn")); System.out.println("ou:"+liMap.get("ou")); System.out.println("o:"+liMap.get("o")); System.out.println(""); } }
原始list:[{cn=Tom, o=company, ou=Sales Department}, {cn=Lily, o=company, ou=HR Department}, {cn=jack, o=company, ou=Financial,product Department}]
cn:Tom
ou:Sales Department
o:company
cn:Lily
ou:HR Department
o:company
cn:jack
ou:Financial,product Department
o:company