1、area函数：Riccati方程求解
2、用法说明
Riccati方程的一般格式是：A'x+xA-xBx+C=0
x=are(A,B,C) A、B、C为上述描述的Riccati方程的系数矩阵，x是方程的解
3、用法实例
>> A = [2 4 3;5 7 3;8 9 2]
A =
2 4 3
5 7 3
8 9 2
>> B = [3 6 4;7 3 9;4 8 2]
B =
3 6 4
7 3 9
4 8 2
>> C = [3 5 1;6 7 2;8 9 3]
C =
3 5 1
6 7 2
8 9 3
>> x = are(A,B,C)
Undefined function 'are' for input arguments of type 'double'.
>> help are
are not found.
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type "help help" for help command options, such as help for methods.