What Is Your Grade?
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 4680 Accepted Submission(s): 1382
Problem Description
“Point, point, life of student!”
This is a ballad（歌谣）well known in colleges, and you must care about your score in this exam too. How many points can you get? Now, I told you the rules which are used in this course.
There are 5 problems in this final exam. And I will give you 100 points if you can solve all 5 problems; of course, it is fairly difficulty for many of you. If you can solve 4 problems, you can also get a high score 95 or 90 (you can get the former(前者) only
when your rank is in the first half of all students who solve 4 problems). Analogically（以此类推）, you can get 85、80、75、70、65、60. But you will not pass this exam if you solve nothing problem, and I will mark your score with 50.
Note, only 1 student will get the score 95 when 3 students have solved 4 problems.
I wish you all can pass the exam!
Come on!
This is a ballad（歌谣）well known in colleges, and you must care about your score in this exam too. How many points can you get? Now, I told you the rules which are used in this course.
There are 5 problems in this final exam. And I will give you 100 points if you can solve all 5 problems; of course, it is fairly difficulty for many of you. If you can solve 4 problems, you can also get a high score 95 or 90 (you can get the former(前者) only
when your rank is in the first half of all students who solve 4 problems). Analogically（以此类推）, you can get 85、80、75、70、65、60. But you will not pass this exam if you solve nothing problem, and I will mark your score with 50.
Note, only 1 student will get the score 95 when 3 students have solved 4 problems.
I wish you all can pass the exam!
Come on!
Input
Input contains multiple test cases. Each test case contains an integer N (1<=N<=100, the number of students) in a line first, and then N lines follow. Each line contains P (0<=P<=5 number of problems that
have been solved) and T（consumed time）. You can assume that all data are different when 0<p.
A test case starting with a negative integer terminates the input and this test case should not to be processed.
have been solved) and T（consumed time）. You can assume that all data are different when 0<p.
A test case starting with a negative integer terminates the input and this test case should not to be processed.
Output
Output the scores of N students in N lines for each case, and there is a blank line after each case.
Sample Input
4 5 06:30:17 4 07:31:27 4 08:12:12 4 05:23:13 1 5 06:30:17 -1#include <stdio.h> int main() { int i,j,n,s,s1,s2; int b[110][5],a[110]; while(scanf("%d",&n)!=EOF) { if(n<0) { break; } for(i=0;i<=n-1;i++) { scanf("%d",&b[i][0]); scanf("%d:%d:%d",&b[i][1],&b[i][2],&b[i][3]); a[i]=b[i][1]*3600+b[i][2]*60+b[i][3]; } for(i=0;i<=n-1;i++) { s1=0; if(b[i][0]==5) { s=100; }else if(b[i][0]==4) { s=90; }else if(b[i][0]==3) { s=80; }else if(b[i][0]==2) { s=70; }else if(b[i][0]==1) { s=60; }else { s=50; } if(s!=100&&s!=50) { for(j=0;j<=n-1;j++) { if(j!=i) { if(b[i][0]==b[j][0]) { s1+=1; } } } s2=0; if(s1!=0) { for(j=0;j<=n-1;j++) { if(j!=i) { if(b[i][0]==b[j][0]) { if(a[j]<a[i]) { s2+=1; if(s2>=(s1+1)/2) { break; } } } } } if(j==n) { s+=5; } } } printf("%d\n",s); } printf("\n"); } return 0; }
Sample Output
100 90 90 95 100
Author
lcy