Problem Description
In this problem we talk about the study of Computer Graphics. Of course, this is very, very hard.
We have designed a new mobile phone, your task is to write a interface to display battery powers.
Here we use '.' as empty grids.
When the battery is empty, the interface will look like this:
We have designed a new mobile phone, your task is to write a interface to display battery powers.
Here we use '.' as empty grids.
When the battery is empty, the interface will look like this:
*------------* |............| |............| |............| |............| |............| |............| |............| |............| |............| |............| *------------*
When the battery is 60% full, the interface will look like this:
*------------* |............| |............| |............| |............| |------------| |------------| |------------| |------------| |------------| |------------| *------------*
Each line there are 14 characters.
Given the battery power the mobile phone left, say x%, your task is to output the corresponding interface. Here x will always be a multiple of 10, and never exceeds 100.
Input
The first line has a number T (T < 10) , indicating the number of test cases.
For each test case there is a single line with a number x. (0 < x < 100, x is a multiple of 10)
For each test case there is a single line with a number x. (0 < x < 100, x is a multiple of 10)
Output
For test case X, output "Case #X:" at the first line. Then output the corresponding interface.
See sample output for more details.
See sample output for more details.
Sample Input
2 0 60
Sample Output
Case #1: *------------* |............| |............| |............| |............| |............| |............| |............| |............| |............| |............| *------------* Case #2: *------------* |............| |............| |............| |............| |------------| |------------| |------------| |------------| |------------| |------------| *------------*
水题不解释
#include <stdio.h> #include <string.h> #include <algorithm> using namespace std; int main() { int T,cas = 1,n,i,j; scanf("%d",&T); while(T--) { scanf("%d",&n); printf("Case #%d:\n",cas++); printf("*------------*\n"); for(i = 0;i<10-n/10;i++) printf("|............|\n"); for(i = 0;i<n/10;i++) printf("|------------|\n"); printf("*------------*\n"); } return 0; }