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hdu 1019

2012年06月16日 ⁄ 综合 ⁄ 共 1161字 ⁄ 字号 评论关闭

Least Common Multiple

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 12188    Accepted Submission(s): 4467

Problem Description

The
least common multiple (LCM) of a set of positive integers is the
smallest positive integer which is divisible by all the numbers in the
set. For example, the LCM of 5, 7 and 15 is 105.

 

Input

Input
will consist of multiple problem instances. The first line of the input
will contain a single integer indicating the number of problem
instances. Each instance will consist of a single line of the form m n1
n2 n3 ... nm where m is the number of integers in the set and n1 ... nm
are the integers. All integers will be positive and lie within the range
of a 32-bit integer.
 

Output

For
each problem instance, output a single line containing the
corresponding LCM. All results will lie in the range of a 32-bit
integer.
 

Sample Input
2
3 5 7 15
6 4 10296 936 1287 792 1
 

Sample Output
105
10296
 

Source

 

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 1 #include <stdio.h>
2 #include <string.h>
3
4 int gcd(int n, int m)
5 {
6 return m ? gcd(m, n % m ) : n;
7 }
8
9 int main( )
10 {
11 int T, i, j, m, n, N, t;
12
13 scanf("%d", &T);
14 while (T--) {
15 scanf("%d", &N);
16 n = m = 1;
17 for( i = 0; i < N; i++) {
18 scanf("%d", &t);
19 m = t / gcd(t, m) * m;
20 //printf("**%d %d\n", m, n);
21 }
22 printf("%d\n",m);
23 }
24 return 0;
25 }

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