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jquery.validationEngine+ajax验证

2013年07月23日 ⁄ 综合 ⁄ 共 1437字 ⁄ 字号 评论关闭

利用jquery.validationEngine ajax验证后台id是否已存在

前台jquery validation框架验证

jsp:

<link rel="stylesheet" type="text/css" href="<%=path%>/js/css/validationEngine.jquery.css"/>
<script type="text/javascript" src="<%=path%>/js/jquery/jquery-1.4.2.min.js"></script>
<script type="text/javascript" src="<%=path%>/js/validation/jquery.validationEngine-cn.js"></script>
<script type="text/javascript" src="<%=path%>/js/validation/jquery.validationEngine.js"></script>

 <input  type="text" name="item.entry" id="item_entry" class="validate[required,custom[onlyNumber],ajax[ajaxItemNoCall],length[0,4]] text-input" size="10"/></td>

 

jquery.validationEngine-cn.js

                "ajaxItemNoCall": {
	                "url": "validateItemNo",
				    "alertText": "* ID已被使用",
				    "alertTextOk": "*ID可以使用",
				    "alertTextLoad": "* 检查中, 请稍候..."
	            }

 

ItemAction.java

 

@Action(results = {@Result(type="json")}, params = { "excludeProperties", "validateReturn"}, value="validateItemNo")
	public String validateItemNo() throws Exception{
		ActionContext ct = ActionContext.getContext();
		HttpServletRequest request= 
			(HttpServletRequest)ct.get(ServletActionContext. HTTP_REQUEST ); 
		String validateId = request.getParameter("fieldId");
		String validateValue = request.getParameter("fieldValue");
		int valiValue = Integer.parseInt(validateValue);
		   
			item = itemService.findItemById(valiValue);
				if(item.getEntry() != valiValue){
					validateReturn[0] = validateId;
					validateReturn[1] = true;
					validateReturn[2] = "可以使用";
				}else {
					validateReturn[0] = validateId;
					validateReturn[1] = false;
					validateReturn[2] = "在指定ID已经存在";
				}
		return "success";
	}

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