其中数据1为100000个字母和数字组成的随机串哈希冲突个数。数据2为100000个有意义的英文句 子哈希冲突个数。数据3为数据1的哈希值与1000003(大素数)求模后存储到线性表中冲突的个数。 数据4为数据1的哈希值与10000019(更大素数)求模后存储到线性表中冲突的个数。 经过比较,得出以上平均得分。平均数为平方平均数。可以发现,BKDRHash无论是在实际效果还是 编码实现中,效果都是最突出的。APHash也是较为优秀的算法。DJBHash,JSHash,RSHash与 SDBMHash各有千秋。PJWHash与ELFHash效果最差,但得分相似,其算法本质是相似的。 在信息修竞赛中,要本着易于编码调试的原则,个人认为BKDRHash是最适合记忆和使用的。 CmYkRgB123原创,欢迎建议、交流、批评和指正。
附:各种哈希函数的C语言程序代码 unsigned int SDBMHash(char *str) { unsigned int hash = 0; while (*str) { // equivalent to: hash = 65599*hash + (*str++); hash = (*str++) + (hash << 6) + (hash << 16) - hash; } return (hash & 0x7FFFFFFF); } // RS Hash unsigned int RSHash(char *str) { unsigned int b = 378551; unsigned int a = 63689; unsigned int hash = 0; while (*str) { hash = hash * a + (*str++); a *= b; } return (hash & 0x7FFFFFFF); } // JS Hash unsigned int JSHash(char *str) { unsigned int hash = 1315423911; while (*str) { hash ^= ((hash << 5) + (*str++) + (hash >> 2)); } return (hash & 0x7FFFFFFF); } // P. J. Weinberger Hash unsigned int PJWHash(char *str) { unsigned int BitsInUnignedInt = (unsigned int)(sizeof(unsigned int) * 8); unsigned int ThreeQuarters = (unsigned int)((BitsInUnignedInt * 3) / 4); unsigned int OneEighth = (unsigned int)(BitsInUnignedInt / 8); unsigned int HighBits = (unsigned int)(0xFFFFFFFF) << (BitsInUnignedInt - OneEighth); unsigned int hash = 0; unsigned int test = 0; while (*str) { hash = (hash << OneEighth) + (*str++); if ((test = hash & HighBits) != 0) { hash = ((hash ^ (test >> ThreeQuarters)) & (~HighBits)); } } return (hash & 0x7FFFFFFF); } // ELF Hash unsigned int ELFHash(char *str) { unsigned int hash = 0; unsigned int x = 0; while (*str) { hash = (hash << 4) + (*str++); if ((x = hash & 0xF0000000L) != 0) { hash ^= (x >> 24); hash &= ~x; } } return (hash & 0x7FFFFFFF); } // BKDR Hash unsigned int BKDRHash(char *str) { unsigned int seed = 131; // 31 131 1313 13131 131313 etc.. unsigned int hash = 0; while (*str) { hash = hash * seed + (*str++); } return (hash & 0x7FFFFFFF); } // DJB Hash unsigned int DJBHash(char *str) { unsigned int hash = 5381; while (*str) { hash += (hash << 5) + (*str++); } return (hash & 0x7FFFFFFF); } // AP Hash unsigned int APHash(char *str) { unsigned int hash = 0; int i; for (i=0; *str; i++) { if ((i & 1) == 0) { hash ^= ((hash << 7) ^ (*str++) ^ (hash >> 3)); } else { hash ^= (~((hash << 11) ^ (*str++) ^ (hash >> 5))); } } return (hash & 0x7FFFFFFF); |