学步园

#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
//using namespace std;

const int maxn = 1005;
int max(int a, int b){ return  a>b ? a:b; }
int min(int a, int b){ return  a<b ? a:b; }
int up[maxn][maxn],left[maxn][maxn],right[maxn][maxn],maze[maxn][maxn],n,m;

/*
up[i][j] : the distance from (i,j) to  (i-t,j) ,where (i-t,j) is the top free sapce (i,j) can straightly get
           there without crossing 'R' space;
           Let we call  the line from (i,j) to  (i-t,j) as "hanging line";
left[i][j] :  the leftmost column position where the hanging line can splay to;   
right[i][j] :  the rightmost column position where the hanging line can splay to;
*/
int main()
{
  int T;
  scanf("%d",&T);
  while(T--){
    scanf("%d %d",&n,&m);
    for(int i=1;i<=n;i++)
       for(int j=1;j<=m;j++){
         int ch=getchar();
         while(ch!='F'&&ch!='R') ch=getchar();
         maze[i][j] = ch=='F' ? 0 : 1;
    }
    for(int i=1;i<=n;i++){
        int lo=0;
        for(int j=1;j<=m;j++){
            if(maze[i][j]==1){
                 left[i][j] = up[i][j]=0; lo=j;
            }
            else {
                left[i][j]= i==1 ? lo+1:max(lo+1,left[i-1][j]);
                up[i][j]= i==1 ? 1 : up[i-1][j]+1;
             }
        }
    }
    int ans=0;
    for(int i=1;i<=n;i++){
       int ro=m+1;
       for(int j=m;j>=1;j--){
           if(maze[i][j]==1){
                 right[i][j] = m; ro=j;
           }
           else {
                right[i][j] = i==1 ? ro-1 : min(ro-1 , right[i-1][j]);
           }
           ans=max(ans,(right[i][j]-left[i][j]+1)*up[i][j]);
       }
    }
    printf("%d\n",ans*3);
  }
  return 0;
}