学步园

深搜或宽搜都可以

#include<iostream>
using namespace std;
int knight[8][8];
int x[]={1,1,2,2,-1,-1,-2,-2};
int y[]={2,-2,1,-1,2,-2,1,-1};
void dfs(int si,int sj,int moves)
{
 if(si<0||sj<0||si>=8||sj>=8||moves>=knight[si][sj])return;
 knight[si][sj]=moves;
 for(int i=0;i<8;i++)
  dfs(si+x[i],sj+y[i],moves+1);
}
int main()
{
 int t;
 cin >> t;
 while(t--)
 {
 char a[10],b[10];
 cin>>a>>b;
  for(int i=0;i<8;i++)
   for(int j=0;j<8;j++)
    knight[i][j]=10;
  dfs(a[0]-'a',a[1]-'1',0);
  cout<<"To get from "<<a<<" to "<<b<<" takes "<<
   knight[b[0]-'a'][b[1]-'1']<<" knight moves."<<endl;
  }
 return 0;
}                                 

还有网上一个

#include<iostream>
#include<queue>
#include<cstdio>
using namespace std;

struct point{
 int x,y;
 int c;
}from,to;

int main(){
 queue<point> q;
 int t;
 char src[3],dist[3];
 int dx[]={1,1,2,2,-1,-1,-2,-2};
 int dy[]={2,-2,1,-1,2,-2,1,-1};
 cin >> t;
 while(t--){
 cin >> src >> dist;
  printf("To get from %s to %s ",src,dist);
  while(!q.empty()) q.pop();
  from.x=src[0]-'a';
  from.y=src[1]-'1';
  from.c=0;
  to.x=dist[0]-'a';
  to.y=dist[1]-'1';
  q.push(from);
  point temp;
  while(true)
  {
   from=q.front();
   q.pop();
   if(from.x==to.x&&from.y==to.y) break;
   for(int i=0;i<8;i++){
    temp.x=from.x+dx[i];
    temp.y=from.y+dy[i];
    temp.c=from.c+1;
    if(temp.x<0||temp.x>7||temp.y<0||temp.y>7)continue;
    q.push(temp);
   }
  }
  printf("takes %d knight moves.\n",from.c);
 }
}