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C语言实现万年历效果

2020年02月13日 编程语言 ⁄ 共 3938字 ⁄ 字号 评论关闭

本文实例为大家分享了C语言实现万年历的具体代码,供大家参考,具体内容如下

#include <stdio.h>#include <stdlib.h>#include <string.h>#define str " SUN MON TUE WED THU FRI SAT " void menu(); //操作菜单int leap(int year); //判断某年是不是闰年int days_month(int year, int month); //返回某月的天数int someday(int year, int month, int day); //计算某天是星期几void search_month(int year, int month); //输出某月的日历void search_someday(int year, int month, int day); //查询某日是星期几 int main(){ int i, year, month, day; int k1, k2, k3, k4; //用于判断输入的数据和操作是否正确,1代表正确,0代表错误 int a = 1; menu(); do { printf("请输入你要进行的操作(1-4):"); scanf_s("%d", &i); getchar(); switch (i) { case 1: printf("请输入你要查询的年份:"); scanf_s("%d", &year); for (a; a <= 12; a++) { printf("\n\n---------******* %d *******------------\n", a); search_month(year, a); } printf("---------*********************------------\n\n\n"); break; case 2: printf("请输入您所要查询的相关信息.\n"); printf("年份:"); scanf_s("%d", &year); printf("月份:"); scanf_s("%d", &month); k1 = 1; while (k1) { if (month > 12 || month < 1) { printf("你输入的月份有误,请重新输入!\n"); printf("月份:"); scanf_s("%d", &month); if (month < 1 || month>12) k1 = 1; } else k1 = 0; } search_month(year, month); printf("---------*********************------------\n\n\n"); break; case 3: printf("请输入你要查询的日期\n"); printf("年份:"); scanf_s("%d", &year); printf("月份:"); scanf_s("%d", &month); k2 = 1; while (k2) { if (month > 12 || month < 1) { printf("你输入的月份有误,请重新输入!\n"); printf("月份:"); scanf_s("%d", &month); if (month < 1 || month>12) k2 = 1; } else k2 = 0; } // printf("%d年%d月有%d天\n",year,month,days_month(year,month)); 调试观察输入的日期是否有误,可忽略 printf("日期:"); scanf_s("%d", &day); k3 = 1; while (k3) { if (day > days_month(year, month) || day < 1) { printf("你输入的日期有误,请重新输入!\n"); printf("日期:"); scanf_s("%d", &day); if (day > days_month(year, month) || day < 1) k3 = 1; } else k3 = 0; } search_someday(year, month, day); printf("---------*********************------------\n\n\n"); break; case 4:exit(0); printf("---------*********************------------\n\n\n"); break; default: k4 = 1; while (k4) { printf("你输入的数据有误,请重新输入你要进行的操作(1-4):"); scanf_s("%d", &i); if (i < 1 || i>4) k4 = 1; else k4 = 0; } break; } } while (i > 0 && i < 5); return 0;} void menu(){ int i = 1; printf("\n\n\t\t----------------------------------------\n"); printf("\t\t|--------------------------------------|\n"); printf("\t\t| %d. 输出某年的日历 |\n", i); printf("\t\t| %d. 输出某月的日历 |\n", i + 1); printf("\t\t| %d. 查询某日是星期几 |\n", i + 2); printf("\t\t| %d. 退出系统 |\n", i + 3); printf("\t\t|--------------------------------------|\n"); printf("\t\t----------------------------------------\n\n"); } int leap(int year){ if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0) return 1; else return 0;} int days_month(int year, int month){ int days_month; switch (month) { case 1: case 3: case 5: case 7: case 8: case 10: case 12: days_month = 31; break; case 4: case 6: case 9: case 11:days_month = 30; break; case 2: if (leap(year) == 1) { days_month = 29; break; } else days_month = 28; break; } return days_month;} int someday(int year, int month, int day){ //该函数运用了特殊的计算公式,详细可参见 http://blog.163.com/hexin_mars_blog/blog/static/248215040201571351115699/ int someday, m, n, i; //someday表示查询的日子是星期几 m = year - year / 1000 * 1000; n = m - m / 100 * 100 - 1; //用于获得年份的后两位数 int days = 0; for (i = 1; i < month; i++) days = days + days_month(year, i); days = days + day; someday = (n + n / 4 - n / 100 + n / 400 + days) % 7; return someday;} void search_someday(int year, int month, int day){ char weekname[20]; switch (someday(year, month, day)) { case 0:strcpy_s(weekname, "星期天"); break; case 1:strcpy_s(weekname, "星期一"); break; case 2:strcpy_s(weekname, "星期二"); break; case 3:strcpy_s(weekname, "星期三"); break; case 4:strcpy_s(weekname, "星期四"); break; case 5:strcpy_s(weekname, "星期五"); break; case 6:strcpy_s(weekname, "星期六"); break; } printf("你所要查询的日期是%s\n", weekname);} void search_month(int year, int month){ int i = 0, j, k = 0, m; //j用于记录某月的第一天是星期几 m用于记录某月的天数 k用于换行提示 char x[10] = " "; m = days_month(year, month); j = someday(year, month, 1); //输出某月的日历 printf("------------------------------------------\n"); printf("%s\n", str); for (; i < j; i++) { printf("%s", x); k++; } for (i = 1; i <= m; i++) { k++; if (k % 7 == 0) { if (i < 10) { printf(" %d ", i); printf("\n"); } else if (i >= 10) { printf(" %d ", i); printf("\n"); } } else { if (i < 10) { printf(" %d ", i); } else if (i >= 10) { printf(" %d ", i); } } } printf("\n------------------------------------------\n");} void exit(){ exit(0);}

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本文标题: C语言实现万年历效果

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