本文指的扫雷是简单模拟电脑中的扫雷游戏，但以我目前的水平，也就只能在黑框中实现
test.c
#include<stdio.h>#include<stdlib.h>#include<time.h>#include "game2.h" void menu(){ printf("********* welcome ********\n"); printf("**********1.play**********\n"); printf("**********0.exit**********\n");}enum Option{ EXIT, PLAY}; void game(){ int x = 0; int y = 0; int i = 0; int win = 0; char mine[ROWS + 2][COLS + 2] = { 0 }; char show[ROWS + 2][ROWS + 2] = { 0 }; init_board(mine, ROWS + 2, COLS + 2, '0'); init_board(show, ROWS + 2, COLS + 2, '*'); //display(mine, ROWS + 2, COLS + 2);#define _CRT_SECURE_NO_WARNINGS //display(show, ROWS + 2, COLS + 2); mine_set(mine, ROWS + 2, COLS + 2); display(mine, ROWS + 2, COLS + 2); while (win<ROWS*COLS - DEFAULT_COUNT) { for (i = 0; i <= win; i++) { printf("请输入坐标:>"); scanf("%d%d", &x, &y); //合法性判断 if ((x>0) && (x <= ROWS) && (y > 0) && (y <= COLS)) { if ((i == 0) && (mine[x][y] == '1')) { (mine[x][y] = '0') ; } if (mine[x][y] == '1') { printf("很遗憾，你被炸死了\n"); break; } else { int count = 0; win++; count = get_mine_num(mine, x, y); show[x][y] = count + '0'; display(show, ROWS + 2, COLS + 2); } } else { printf("输入错误请重新输入\n"); } } if (win >= ROWS*COLS - DEFAULT_COUNT) { printf("恭喜你，扫雷成功\n"); } }}int main(){ int input = 0; srand((uint_t)time(NULL)); do { menu(); printf("请选择:>"); scanf("%d", &input); switch (input) { case PLAY: game(); break; case EXIT: break; default: printf("输入错误，请重新输入\n"); break; } } while (input); system("pause\n"); return 0;}
game.c
#define _CRT_SECURE_NO_WARNINGS 1#include "game2.h"#include<stdlib.h>#include<stdio.h>#include<string.h> void init_board(char arr[ROWS + 2][COLS + 2], int row, int col,char ch){ memset(arr, ch, sizeof(char) * row * col);}void display(char arr[ROWS + 2][COLS + 2], int row, int col){ int i = 0; int j = 0; printf(" "); for (i = 0; i < col - 2; i++) { printf("%d ", i + 1); } printf("\n"); for (i = 0; i < row - 2; i++) { printf("%2d ", i + 1); for (j = 0; j < col - 2; j++) { printf("%c ", arr[i + 1][j + 1]); } printf("\n"); }}void mine_set(char arr[ROWS + 2][COLS + 2], int row, int col){ int x = 0; int y = 0; int count = DEFAULT_COUNT; while (count) { x = rand() % 10 + 1; y = rand() % 10 + 1; if (arr[x][y] != '1') { arr[x][y] = '1'; count--; } }}int get_mine_num(char arr[ROWS + 2][COLS + 2], int x, int y){ return (arr[x][y - 1] - '0') + (arr[x - 1][y - 1]-'0')- + (arr[x - 1][y]-'0') + (arr[x - 1][y + 1]-'0') + (arr[x][y + 1]-'0') + (arr[x + 1][y + 1]-'0') + (arr[x + 1][y]-'0') + (arr[x + 1][y - 1]-'0');//返回周围雷的个数}
game.h
#ifndef __GAME_H__#define __GAME_H__ #define ROWS 10#define COLS 10#define DEFAULT_COUNT 20typedef unsigned int uint_t;//类型重命名 #include<string.h>#include<stdio.h>#include<time.h>#include<stdlib.h> void init_board(char arr[ROWS + 2][COLS + 2], int row, int col,char ch);//初始化void display(char arr[ROWS + 2][COLS + 2], int row, int col);void mine_set(char arr[ROWS + 2][COLS + 2], int row, int col);//放雷int get_mine_num(char arr[ROWS + 2][COLS + 2], int row, int col);//统计坐标周围雷的个数 #endif //__GAME_H__
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本文标题: C语言模拟实现简单扫雷游戏
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