学步园

题目链接：http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=1346

题目大意：赤裸裸的最长递增子序列。

解题思路：状态转移方程：if (arr[i] == brr[i]) dp[i][j] = max(dp[i][j],dp[i-1][j-1]  + 1);

                                          else                     dp[i][j] = max(dp[i][j-1],dp[i-1][j]);

测试数据：

a1b2c3d4e
zz1yy2xx3ww4vv

abcdefghijklmnopqrstuvwxyz
a0b0c0d0e0f0g0h0i0j0k0l0m0n0o0p0q0r0s0t0u0v0w0x0y0z0

abcdefghijklmnzyxwvutsrqpo
opqrstuvwxyzabcdefghijklmn



代码：
#include <stdio.h>
#include <string.h>
#define MAX 1100
#define max(a,b) (a) > (b) ? (a) : (b)


int n,m,ans,dp[MAX][MAX];
char fstr[MAX],sstr[MAX];


int main()
{
	int i,j,k,t;


	while (gets(fstr+1) != NULL) {

		gets(sstr+1);
		memset(dp,-1,sizeof(dp));
		ans = 0;
		n = strlen(fstr+1);
		m = strlen(sstr+1);
		for (i = 0; i <= n; ++i)
			dp[i][0] = 0;
		for (j = 0; j <= m; ++j)
			dp[0][j] = 0;


		for (i = 1; i <= n; ++i)
			for (j = 1; j <= m; ++j) {

				if (fstr[i] == sstr[j])
					dp[i][j] = max(dp[i][j],dp[i-1][j-1]+1);
				else dp[i][j] = max(dp[i-1][j],dp[i][j-1]);
				ans = max(dp[i][j],ans);
			}

		
		printf("%d\n",ans);
	}
}



本文ZeroClock原创，但可以转载，因为我们是兄弟。