学步园

题目：题目链接

题意：如题，就是判断长和宽的可以变成的偶数的个数

代码：

#include <iostream>
#include <cstdio>
#include <string>
#include <string.h>
#include <map>
#include <vector>
#include <cstdlib>
#include <algorithm>
#include <cmath>
#include <queue>
#include <set>
#include <stack>
#include <functional>
#include <fstream>
#include <sstream>
#include <iomanip>
#include <numeric>
#include <cassert>
#include <bitset>
#include <stack>
#include <ctime>
#include <list>
#define INF 0x7fffffff
#define max3(a,b,c) (max(a,b)>c?max(a,b):c)
#define min3(a,b,c) (min(a,b)<c?min(a,b):c)
#define mem(a,b) memset(a,b,sizeof(a))
using namespace std;

int QuickMod(int  a,int b,int n)
{
    int r = 1;
    while(b)
    {
        if(b&1)
            r = (r*a)%n;
        a = (a*a)%n;
        b >>= 1;
    }
    return r;
}

int main()
{
    int t;
    scanf("%d", &t);
    int c, l;
    while(t--)
    {
        scanf("%d%d", &l, &c);
        int f1 = 0, f2 = 0;
        while(l%2==0)
        {
            f1++;
            l /= 2;
        }
        while(c%2==0)
        {
            f2++;
            c /= 2;
        }
        if((f1+f2)%2 == 0)printf("Adivon prevails\n");
        else printf("Adidas loses\n");
    }
    return 0;
}