python机器学习包里面的cluster提供了很多聚类算法,其中ward_tree实现了凝聚层次聚类算法。
但是没有看明白ward_tree的返回值代表了什么含义,遂决定寻找别的实现方式。
经过查找,发现scipy.cluster.hierarchy.fclusterdata能够实现层次聚类。有关这个方法的介绍在:http://docs.scipy.org/doc/scipy/reference/generated/scipy.cluster.hierarchy.fclusterdata.html
以下是具体的python代码
#coding=utf8 """ # Author: waleking # Created Time : 四 7/26 17:05:07 2012 Last Modified: 二 7/31 17:56:26 2012 # File Name: hierachical.py # Description: 使用sklearn的层次聚类方法,具体的是ward_tree方法 测试数据采用iris数据,sklearn.datasets.load_iris() 但是发现sklearn.cluster.ward_tree方法没有看懂,实验stackoverflow里面的代码 http://stackoverflow.com/questions/9873840/cant-get-scipy-hierarchical-clustering-to-work """ import sklearn.datasets as datasets import scipy.cluster.hierarchy as hcluster import numpy.random as random import numpy as np import numpy.core.fromnumeric import time import matplotlib.pyplot as plt def irisSample(): iris=datasets.load_iris() irisdata=iris.data result=hcluster.fclusterdata(irisdata, criterion='maxclust',t=3) print("result is %s" % result) def gaussianSample(): timeCheckin=time.clock() X=random.randn(100,100) X[:50,:100]+=10 result=hcluster.fclusterdata(X, criterion='maxclust',t=2) print("hierachical clustering on sample with shape(%d,%d) cost %s seconds " % (np.shape(X)[0],np.shape(X)[1],time.clock()-timeCheckin)) print("result is %s" % result) clusterA=[label for label in result if(label==1)] clusterB=[label for label in result if(label==2)] print("There are %d samples in cluster 1" %(len(clusterA))) print("ClusterA is %s" % clusterA) print("There are %d samples in cluster 2" %(len(clusterB))) print("ClusterB is %s" % clusterB) def testPerformanceByNum(start,end,increment): """测试样本数对性能的影响 """ mapPerformance=dict() for sampleNum in range(start,end,increment): X=random.randn(sampleNum,100) X[:50,:100]+=10 timeCheckin=time.clock() result=hcluster.fclusterdata(X,criterion='maxclust',t=2) timeCost=time.clock()-timeCheckin mapPerformance[sampleNum]=timeCost return mapPerformance def testPerformanceByDim(start,end,increment): """测试维度对性能的影响 """ mapPerformance=dict() for dim in range(start,end,increment): X=random.randn(100,dim) X[:50,:dim]+=10 timeCheckin=time.clock() result=hcluster.fclusterdata(X,criterion='maxclust',t=2) timeCost=time.clock()-timeCheckin mapPerformance[dim]=timeCost return mapPerformance def showPerformance(mapPerformance): """画图,展现性能 """ xAxisData=numpy.core.fromnumeric.sort(mapPerformance.keys()) yAxisData=[mapPerformance[key] for key in xAxisData] plt.plot(xAxisData,yAxisData,'*-') plt.show() #irisSample() #gaussianSample() mapPerformance=testPerformanceByNum(100,3100,100) showPerformance(mapPerformance) mapPerformance=testPerformanceByDim(100,10100,100) showPerformance(mapPerformance)
我们测试了100维的数据的层次聚类,随机生成100个到3000个服从高斯分布的数据,让50个点的均值不同于其余的点。
测试的性能图如下:
我们又测试了固定样本数:100个样本,服从高斯分布,其中50个的均值不同于另外的50个。我们实验了维度从100变化到10000,得到性能图如下:
结论:层次聚类的时间复杂度是O(m^2 n),和Andrew Ng在机器学习课程中的符号相同,其中样本数是m,维度是n,