转自：http://zhiwei.li/text/2010/08/%E4%BF%AE%E5%A4%8Dsqlite-database-disk-image-is-malformed/
运行某些SQL语句出错database disk image is malformed
说明SQLite的内部数据格式,已经损坏
sqlite> PRAGMA integrity_check;
*** in database main ***
Main freelist: 3 of 3 pages missing from overflow list starting at 0
排除磁盘空间不够的原因
修复步骤
$ sqlite3 backup.sqlite
sqlite> .output “_temp.tmp”
sqlite> .dump
sqlite> .quit
$ sqlite3 new.sqlite
sqlite> .read “_temp.tmp”
sqlite> .quit
就将错误的backup.sqlite修复为new.sqlite了
另一种更快的修复方法
$echo “.dump” | sqlite3 old.db | sqlite3 new.db
直接将 old.db 修复为 new.db
或者
sqlite3 newsfeed.db .dump > newsfeed.sql
sqlite3 newsfeed.db < newsfeed.sql
请参考 http://www.sqlite.org/faq.html#q21
http://www.sqlite.org/sqlite.html
PHP使用popen调用sqlite shell来实现修复
$handle = popen(“mv ../backup.sqlite bad.sqlite && sqlite3 bad.sqlite .dump | sqlite3 good.sqlite && mv good.sqlite ../backup.sqlite”, ‘r’);
$read = fread($handle, 4096);
echo $read;
pclose($handle);
压缩
sqlite3 my.sqlite 'VACUUM;'