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<p>斐波纳数列fib(n)=fib(n-1)+fib(n-2),当n小于等于1时，结果为n</p>
<script type="text/javascript">
function fib(n){
if(n<=1)
return n;
else
return fib(n-1)+fib(n-2);
}
//使用非递归方式实现fib
function fib2(n){
if(n<=1)
return n;
else{
var pre=0,now=1,next=0;
for(var j=2;j<=n;j++){
next=pre+now;
pre=now;
now=next;
}
return next;
}
}
alert("fib(6)="+fib(6));
</script>
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