最近要解决用2维矩阵拟合2维函数的问题,貌似在中文网站中没有找到方法,最后在stack overflow才问到了答案,解答如下。
假设有5*5数组:
d= [0.0177104427823448,0.00246661459209512,0.0399831543374395,0.0615494164555707,0.0476204124707652;0.0275276152854314,0.0219153841813084,0.0581144391404502,0.144890028400954,0.157839631316098;0.0622883972729130,0.0716157303159909,0.245482781674067,0.123999612575059,0.177495187746408;0.0200735764542146,0.0573087934038160,0.0636451189717613,0.016081008456841......
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