1.题目：
Problem Description
设计一个矩阵类Data，包括矩阵的行、列、矩阵数据等私有数据成员。要求实现两个矩阵的加。
Input
输入数据有多组，每组输入数据有三行，第一行两个整数，分别代表矩阵的行数m和列数n；第二行有m*n个整数，是第一个矩阵的数据；第三行也有m*n个整数，是第二个矩阵的数据。
Output
对于每组输入数据，输出两个矩阵的和。
Sample Input
3 3
1 1 1 2 2 2 3 3 3
1 1 1 1 1 1 1 1 1
2 3
1 2 3 4 5 6
1 1 1 1 1 1
Sample Output
2 2 2
3 3 3
4 4 4
2 3 4
5 6 7
2.下面这个代码没有真正达到目的：
#include <iostream>
using namespace std;
#define N 500
class Data{
private:
int row, col, *a;
public:
Data();
Data(int* b, int& l, int& r);
Data operator+(Data&);
void show();
};
Data::Data()
{
row = 0;
col = 0;
int* b = new int[N];
a = b;
}
Data::Data(int* b, int& l, int& r)
{
row = l;
col = r;
a = b;
}
Data Data::operator+(Data& c)
{
Data sum;
sum.row = c.row;
sum.col = c.col;
for (int i = 0; i < row * col; i++)
sum.a[i] = a[i] + c.a[i];
return sum;
}
void Data::show()
{
int i, j, k = 0;
for (i = 0; i < row; i++) {
for (j = 0; j < col; j++) {
if (j == 0)
cout << a[k++];
else
cout << ' ' << a[k++];
}
cout << endl;
}
}
int main()
{
int m, n, i, j, a[N], b[N];
while (cin >> m >> n) {
for (i = 0; i < m * n; i++)
cin >> a[i];
for (j = 0; j < m * n; j++)
cin >> b[j];
Data x(a, m, n), y(b, m, n), z;
z = x + y;
z.show();
}
return 0;
}
看看现在这段代码：
#include <iostream>
//#include <stdio.h>
using namespace std;
class Matrix
{
const int row, col;
int* a;
public:
Matrix(int r, int c);
Matrix(Matrix& m);
~Matrix();
Matrix& operator=(Matrix& m);
Matrix operator+(Matrix& m);
friend istream& operator>>(istream& in, Matrix& m);
friend ostream& operator<<(ostream& out, Matrix& m);
};
Matrix::Matrix(int r, int c): col(c), row(r)
{
int i;
a = new int[r * c];
for (i = 0; i < r * c; i++)
a[i] = 0;
}
Matrix::Matrix(Matrix& m): col(m.col), row(m.row)
{
int i;
a = new int[col * row];
for (i = 0; i < col * row; i++)
a[i] = m.a[i];
}
Matrix::~Matrix()
{
delete []a;
}
Matrix& Matrix::operator=(Matrix& m)
{
int i;
if (m.row == row && m.col == col)
for (i = 0; i < row * col; i++)
a[i] = m.a[i];
return *this;
}
Matrix Matrix::operator+(Matrix& m)
{
Matrix b(m.row, m.col);
int i;
for (i = 0; i < row * col; i++)
b.a[i] = m.a[i] + a[i];
return b;
}
istream& operator>>(istream& in, Matrix& m)
{
int i;
for (i = 0; i < m.row * m.col; i++) {
cin >> m.a[i];
}
return in;
}
ostream& operator<<(ostream& out, Matrix& m)
{
int i, j;
for (i = 0; i < m.row; i++) {
for (j = 0; j < m.col; j++) {
if (j == 0)
cout << m.a[i * m.col + j];
else
cout << " " << m.a[i * m.col + j];
}
cout << endl;
}
return out;
}
int main()
{
// freopen("1.txt", "r", stdin);
int a, b;
while (cin >> a >> b) {
Matrix x(a, b);
cin >> x;
Matrix y(a, b);
cin >> y;
cout << x + y;
}
return 0;
}