下面的这个例子提供了DataGrid快速添加新行的功能。aspx代码和Cohe Behind代码分别如下，注意更改数据录连接字符串：
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InsertableDataGrid.aspx
<%@ Page Language="vb" AutoEventWireup="false" Codebehind="InsertableDataGrid.aspx.vb" Inherits="aspxWeb.InserTableDataGrid"%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML>
<HEAD>
<title>WebForm1</title>
<meta name="GENERATOR" content="Microsoft Visual Studio.NET 7.0">
<meta name="CODE_LANGUAGE" content="Visual Basic 7.0">
<meta name="vs_defaultClientScript" content="JavaScript">
<meta name="vs_targetSchema" content="http://schemas.microsoft.com/intellisense/ie5">
</HEAD>
<body MS_POSITIONING="GridLayout">
<form id="Form1" method="post" runat="server">
<asp:DataGrid id="DataGrid1" runat="server" BorderColor="#CC9966" BorderStyle="None"
BorderWidth="1px" BackColor="White" CellPadding="4" ShowFooter="True" AutoGenerateColumns="False">
<SelectedItemStyle Font-Bold="True" ForeColor="#663399" BackColor="#FFCC66"></SelectedItemStyle>
<ItemStyle ForeColor="#330099" BackColor="White"></ItemStyle>
<HeaderStyle Font-Bold="True" ForeColor="#FFFFCC" BackColor="#990000"></HeaderStyle>
<FooterStyle ForeColor="#330099" BackColor="#FFFFCC"></FooterStyle>
<Columns>
<asp:TemplateColumn HeaderText="Employee ID">
<ItemTemplate>
<asp:Label id=Label3 runat="server" Text='<%# DataBinder.Eval(Container, "DataItem.employeeid") %>'>
</asp:Label>
</ItemTemplate>
<FooterTemplate>
<asp:LinkButton id="LinkButton1" runat="server" CommandName="Insert">Insert</asp:LinkButton>
</FooterTemplate>
<EditItemTemplate>
<asp:TextBox id=TextBox5 runat="server" Text='<%# DataBinder.Eval(Container, "DataItem.employeeid") %>'>
</asp:TextBox>
</EditItemTemplate>
</asp:TemplateColumn>
<asp:TemplateColumn HeaderText="Last Name">
<ItemTemplate>
<asp:Label id=Label1 runat="server" Text='<%# DataBinder.Eval(Container, "DataItem.lastname") %>'>
</asp:Label>
</ItemTemplate>
<FooterTemplate>
<asp:TextBox id="TextBox2" runat="server"></asp:TextBox>
</FooterTemplate>
<EditItemTemplate>
<asp:TextBox id="TextBox1" runat="server"></asp:TextBox>
</EditItemTemplate>
</asp:TemplateColumn>
<asp:TemplateColumn HeaderText="First Name">
<ItemTemplate>
<asp:Label id=Label2 runat="server" Text='<%# DataBinder.Eval(Container, "DataItem.firstname") %>'>
</asp:Label>
</ItemTemplate>
<FooterTemplate>
<asp:TextBox id="TextBox4" runat="server"></asp:TextBox>
</FooterTemplate>
<EditItemTemplate>
<asp:TextBox id="TextBox3" runat="server"></asp:TextBox>
</EditItemTemplate>
</asp:TemplateColumn>
</Columns>
<PagerStyle HorizontalAlign="Center" ForeColor="#330099" BackColor="#FFFFCC"></PagerStyle>
</asp:DataGrid>
</form>
</body>
</HTML>
InsertableDataGrid.aspx.vb
Imports System.Data
Imports System.Data.SqlClient
Public Class InserTableDataGrid
Inherits System.Web.UI.Page
Protected WithEvents DataGrid1 As System.Web.UI.WebControls.DataGrid
#Region " Web Form Designer Generated Code "
'This call is required by the Web Form Designer.
<System.Diagnostics.DebuggerStepThrough()> Private Sub InitializeComponent()
End Sub
Private Sub Page_Init(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Init
'CODEGEN: This method call is required by the Web Form Designer
'Do not modify it using the code editor.
InitializeComponent()
End Sub
#End Region
Dim connstr As String = "Integrated Security=SSPI;User ID=sa;Initial Catalog=NorthWind;Data Source=./netsdk"
Private Sub Page_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
If Not Page.IsPostBack Then
BindGrid()
End If
End Sub
Sub BindGrid()
Dim cnn As New SqlConnection(connstr)
Dim da As New SqlDataAdapter("select employeeid,lastname,firstname from employees", cnn)
Dim ds As New DataSet()
da.Fill(ds, "employees")
DataGrid1.DataSource = ds
DataGrid1.DataBind()
End Sub
Private Sub DataGrid1_ItemCommand(ByVal source As Object, ByVal e As System.Web.UI.WebControls.DataGridCommandEventArgs)_
Handles DataGrid1.ItemCommand
If e.CommandName = "Insert" Then
Dim cnn As New SqlConnection(connstr)
Dim t1 As TextBox = e.Item.FindControl("textbox2")
Dim t2 As TextBox = e.Item.FindControl("textbox4")
cnn.Open()
Dim cmd As New SqlCommand("insert into employees(lastname,firstname) values('" & t1.Text & "','" & t2.Text & "')", cnn)
cmd.ExecuteNonQuery()
cnn.Close()
BindGrid()
End If
End Sub
End Class