学步园

Java中的private函数是不能被继承的, 即基类中如果有一个private函数func(), 现在在子类中实现一个与其同名,参数列表也相同的func

()函数,这两个函数之间只是简单的覆盖关系,不能使用多态.

但是C++中可以被继承,使用多态性质.

#include <iostream><br /> using namespace std;</p> <p>class Base<br /> {<br /> private:<br /> virtual void func()<br /> {<br /> cout<<"this is func() in Base."<<endl;<br /> }<br /> public:<br /> Base(void);<br /> virtual ~Base(void);<br /> void callfunc()<br /> {<br /> cout<<"callfunc() in Base."<<endl;<br /> func();<br /> }<br /> };</p> <p>class derived1 :<br /> public Base<br /> {<br /> private:<br /> void func()<br /> {<br /> cout<<"this is func() in derived1."<<endl;<br /> }<br /> public:<br /> derived1(void);<br /> virtual ~derived1(void);<br /> };</p> <p>int main()<br /> {<br /> Base* one = new Base();<br /> Base* second = new derived1();<br /> one->callfunc();<br /> second->callfunc();<br /> delete one;<br /> delete second;<br /> }<br />

打印结果:

callfunc() in Base.

this is func() in Base.

callfunc() in Base.

this is func() in derived1.