学步园

不就是个进制转换嘛，写的这么复杂

#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;
int solve(int in[],int out[], int a, int b)
{
int i, j, k=0, yu, temp[1000];
while(in[0]>0)
{
   memset(temp,0,sizeof(temp[0])*1000);
   i = in[0];
   yu = 0;
   temp[0] = in[0]; 
   while(i > 0)
   {
    yu = yu*a + in[i];
    temp[i --] = yu/b;
    yu %= b;
   }
   out[++k] = yu;
   i = in[0] ;
   while(i>0 && temp[i] == 0)
   {
    i --;
    temp[0] --;
   }
   memset(in,0,sizeof(in[0])*1000);
   for(i=0; i<=temp[0]; i++)
    in[i] = temp[i];
}
return k;
}
int main()
{
int n, i, a, b, f,len,in[1000], out[1000];
char s[1000];
while(cin>>s>>a>>b)
{
   len = strlen(s);
   for(i = 0; i<len; i++)
   {
    if(s[i]>='A' && s[i]<='Z')
     in[len - i] = s[i] - 'A' + 10;
    else if(s[i]>='a' && s[i]<='z')
     in[len - i ] = s[i] - 'a' + 36;
    else in[len - i] = s[i] - '0';
   }
   in[0] = len;
   f = solve(in,out,a,b);
   if(f>7)
   {
    cout<<"  ERROR"<<endl;
    continue;
   }
   for(i=0; i<7-f; i++)
    cout<<' ';
   for(i = f; i>0; i--)
   {
    if(out[i]>=10 && out[i]<= 35)
     printf("%c",out[i] - 10 + 'A');
    else if(out[i]>=36 && out[i] <= 61)
     printf("%c",out[i] - 36 + 'a'); 
    else printf("%d",out[i]);
   }
   cout<<endl;
   memset(in,0,sizeof(in[0])*1000);
   memset(out,0,sizeof(out[0]*1000));
   memset(s,'\0',sizeof(s[0])*1000);
}
return 0;
}