学步园

题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=4578

多种操作，都是对区间的操作，

#include <iostream>
#include <stdio.h>
#include <stdlib.h>
#include <algorithm>
#include <string.h>
using namespace std;

#define mode 10007
#define maxn 100010
#define lson l,m,rt<<1
#define rson m+1,r,rt<<1|1

int n,m;
int col[maxn<<2];
int val[maxn<<2];

int power(int a,int p){
    if(p == 1) return a%mode;
    else if(p == 2) return (a%mode*a)%mode;
    else return ((a*a)%mode*a)%mode;
}

void PushUp(int rt){
    if((col[rt<<1]) && (col[rt<<1|1]) && (val[rt<<1] == val[rt<<1|1])){
            col[rt] = 1;
            val[rt] = val[rt<<1];
    }
}

void Pushdown(int rt){
    if(col[rt]){
        col[rt<<1] = col[rt<<1|1] = 1;
        val[rt<<1] = val[rt<<1|1] = val[rt];
        col[rt] = 0;
    }
}

void update(int L,int R,int c,int op,int l,int r,int rt){
    if(op == 1 && col[rt] && L <= l && r <= R){
        val[rt] =(val[rt] + c) % mode;
        return ;
    }
    if(op == 2 && col[rt] &&L <= l && r <= R){
        val[rt] =(val[rt] * c)  % mode;
        return ;
    }
    if(op == 3&& L <= l && r <= R){
        col[rt] = 1;
        val[rt] = c%mode;
        return;
    }
    //return ;
    Pushdown(rt);
    int m = (l + r) /2;
    if(L <= m) update(L,R,c,op,lson);
    if(m <  R) update(L,R,c,op,rson);
    PushUp(rt);
}

int query(int L,int R,int p,int l,int r,int rt){
    if(L <= l && r <= R){
        if(col[rt]){
                //cout <<  power(val[rt],p) <<endl;
            return power(val[rt],p)*(r - l + 1);
        }
    }
    int m = (l + r)/2;
    Pushdown(rt);
    int ret = 0;
    if(L <= m) ret += query(L,R,p,lson);
    if(m <  R) ret += query(L,R,p,rson);
    return ret%mode;
}

int main()
{
    while(~scanf("%d %d",&n,&m)){
        if(n == 0 && m ==0) break;
        memset(val,0,sizeof(val));
        col[1]= 1;
        int op,a,b,c;
        while(m--){
            scanf("%d %d %d %d",&op,&a,&b,&c);
            if(op<4) update(a,b,c,op,1,n,1);
            else{
                int ans = (query(a,b,c,1,n,1) + mode)%mode;
                printf("%d\n",ans);
            }
        }
    }
    return 0;
}