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Chapter 2 Linked Lists – 2.3

2013年10月11日 ⁄ 综合 ⁄ 共 1011字 ⁄ 字号 评论关闭

Problem 2.3: Implement an algorithm to delete a node in the middle of a single linked list, given only access to that node.
EXAMPLE
Input: the node 'c' from the linked list a->b->c->d->e
Result: nothing is returned, but the new linked list looks like a->b->d->e

At first sight, it is impossible to solve it without information of the left segment of the linked list. However, I quickly found that we can not only reorganize relations among nodes, but also change the data of nodes. The solution is given below:

class node:
    def __init__(self, data = None):
        self.data = data
        self.next = None

def delete_middle(node):
    # Shift the values of nodes
    # and the value of given node will
    # be overwritten (deleted)
    node_pre = None
    while node.next != None:
        node_pre = node
        node.data = node.next.data
        node = node.next
    # Delete the last node
    node_pre.next = None
    del node

However, my solution is not better than the one answer page. Actually, we can just shift once and delete the next node.

def delete_middle(node):
    node.data = node.next.data
    node_next = node.next
    node.next = node.next.next
    del node_next

Next time when I come up with a idea that seems "smart", I should try to verify it and improve it, rather than implement it.

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