学步园

对于可以补的subject 应该优先考虑分数大的 并且尽量延后时间，只需要按照分值大小排序然后依次安排即可

#include<iostream>
#include<cstring>
#include<algorithm>
#include<cstdio>
#include<vector>
#include<string>
#include<cmath>
#include<deque>
#include<map>
#include<queue>
#define iinf 0x7f7f7f7f
#define linf 1000000000000000000LL
#define dinf 1e200
#define eps 1e-11
#define lng long long
#define sqr(a) ((a)*(a))
#define pii pair<int,int>
#define X first
#define Y second
#define pi 3.14159265359
#define cc(i,j) memset(i,j,sizeof(i))
#define two(x)          ((lng)1<<(x))
#define mod  9901
#define pmod(x,y) (x%y+y)%y
#include<set>
using namespace std;
typedef vector<int>  vi;
typedef vector<string>  vs;
template<class T> inline void checkmax(T &x,T y){if(x<y) x=y;}
template<class T> inline void checkmin(T &x,T y){if(x>y) x=y;}
template<class T> inline T Min(T x,T y){return (x>y?y:x);}
template<class T> inline T Max(T x,T y){return (x<y?y:x);}
template<class T> T Abs(T a){return a>0?a:(-a);}
int ncase;
int n,sum;
pii d[1111];
bool is[2222];
bool cmp(pii p,pii q)
{
    return p.X>q.X;
}
int main()
{
   scanf("%d",&ncase);
   while(ncase--)
   {
       scanf("%d",&n);
       sum=0;
       for(int i=1;i<=n;++i)
       scanf("%d",&d[i].Y);
       for(int i=1;i<=n;++i)
       {
           scanf("%d",&d[i].X);
       }
       sort(d+1,d+1+n,cmp);
       cc(is,0);
       for(int i=1;i<=n;++i)
       {
           for(int j=d[i].Y;j>=0;--j)
           {
               if(j==0)
               sum+=d[i].X;
               else
               if(!is[j])
               {
                   is[j]=1;
                   break;
               }
           }
       }
       printf("%d\n",sum);
   }
    return 0;
}