1 接上一篇文章<Spring 注解版简单实例(一)>,此处为 @Component与@Resource相结合
在applicationContext.xml 文件中使用<context:component-scan>的效果,大大的减少了配置文件的书写,只添加一句
<context:component-scan base-package="com.bjsxt"/> 扫描包的路径
<?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-2.5.xsd"> <context:annotation-config /> <context:component-scan base-package="com.bjsxt"/> </beans>
2 在UserServer和UserDAo类中分别更改为
UserSevice
package com.bjsxt.service; import javax.annotation.Resource; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.beans.factory.annotation.Qualifier; import org.springframework.stereotype.Component; import com.bjsxt.dao.UserDAO; import com.bjsxt.model.User; @Component("userService") public class UserService { private UserDAO userDAO; public void init() { System.out.println("init"); } public void add(User user) { userDAO.save(user); } public UserDAO getUserDAO() { return userDAO; } @Resource(name="u") public void setUserDAO( UserDAO userDAO) { this.userDAO = userDAO; } }
userDAO
package com.bjsxt.dao.impl; import org.springframework.stereotype.Component; import com.bjsxt.dao.UserDAO; import com.bjsxt.model.User; @Component("u") public class UserDAOImpl implements UserDAO { public void save(User user) { //Hibernate //JDBC //XML //NetWork System.out.println("user saved!"); } }
3执行效果和以前的一样