现在的位置: 首页 > 综合 > 正文

Access UPdate 标准表达式中数据类型不匹配

2012年11月16日 ⁄ 综合 ⁄ 共 2195字 ⁄ 字号 评论关闭

一直没机会用ASP.NET操作ACCESS数据库,今天一用就让我遇到一个很奇怪的问题

在UPdate操作时遇到一个"标准表达式中数据类型不匹配"错误~到现在我也没搞明是什么原因,添加,删除,查询都没问题,就只有在更新操作时会有问题,我尝试了一下将ID直接写到字符串中,不通过参数,这样就成功了

问题代码:

StringBuilder strSql = new StringBuilder();
            strSql.Append("update RGP_AuthorityDir set ");
            strSql.Append("AuthorityName=@AuthorityName,");
            strSql.Append("AuthorityTag=@AuthorityTag,");
            strSql.Append("AuthorityDescription=@AuthorityDescription,");
            strSql.Append("AuthorityOrder=@AuthorityOrder");
            strSql.Append(" where AuthorityID=@AuthorityID ");
            OleDbParameter[] parameters = {
     new OleDbParameter("@AuthorityID", OleDbType.Integer,11),
                    new OleDbParameter("@AuthorityName", OleDbType.VarWChar,30),
                    new OleDbParameter("@AuthorityTag", OleDbType.VarWChar,50),
                    new OleDbParameter("@AuthorityDescription", OleDbType.VarWChar,50),
                    new OleDbParameter("@AuthorityOrder", OleDbType.Integer,11)};
            parameters[0].Value = model.AuthorityID;
            parameters[1].Value = model.AuthorityName;
            parameters[2].Value = model.AuthorityTag;
            parameters[3].Value = model.AuthorityDescription;
            parameters[4].Value = model.AuthorityOrder;

 解决办法

StringBuilder strSql = new StringBuilder();
            strSql.Append("update RGP_AuthorityDir set ");
            strSql.Append("AuthorityName=@AuthorityName,");
            strSql.Append("AuthorityTag=@AuthorityTag,");
            strSql.Append("AuthorityDescription=@AuthorityDescription,");
            strSql.Append("AuthorityOrder=@AuthorityOrder");
            strSql.Append(" where AuthorityID=" + model.AuthorityID);
            OleDbParameter[] parameters = {
                    new OleDbParameter("@AuthorityName", OleDbType.VarWChar,30),
                    new OleDbParameter("@AuthorityTag", OleDbType.VarWChar,50),
                    new OleDbParameter("@AuthorityDescription", OleDbType.VarWChar,50),
                    new OleDbParameter("@AuthorityOrder", OleDbType.Integer,11)};
            parameters[0].Value = model.AuthorityName;
            parameters[1].Value = model.AuthorityTag;
            parameters[2].Value = model.AuthorityDescription;
            parameters[3].Value = model.AuthorityOrder;   

抱歉!评论已关闭.