学步园

/*  

实验内容:定义Complex类中的<<和>>运算符的重载，实现输入和输出。  

* 程序的版权和版本声明部分   

* Copyright (c) 2011, 烟台大学计算机学院学生   

* All rights reserved.   

* 文件名称： 定义Complex类中的<<和>>运算符的重载，实现输入和输出                              

* 作    者：   付文杰                         

* 完成日期：  2012       年  4    月  16日   

* 版 本号：  x1.0          

* 对任务及求解方法的描述部分   

* 输入描述： 

* 程序头部的注释结束（此处也删除了斜杠）   

*/  

//【任务1】接第8周任务1，定义Complex类中的<<和>>运算符的重载，实现输入和输出，改造原程序中对运算结果显示方式，使程序读起来更自然。
  

#include <iostream>

using namespace std;

class Complex
{
public:
	Complex(){real = 0; imag = 0;}
	Complex(double r){real = r;imag = 0;}//类型转换函数
	
	Complex(double r,double i){real = r; imag = i;}

	friend ostream& operator << (ostream &,Complex &);
	friend istream& operator >> (istream &,Complex &);

	friend Complex operator+ (Complex c1,Complex c2);
	friend Complex operator- (Complex c1, Complex c2);
	friend Complex operator- (Complex &c);
	friend Complex operator* (Complex c1, Complex c2);
	friend Complex operator/ (Complex c1, Complex c2);
private:
	double real;
	double imag;
};
//下面定义成员函数
ostream& operator << (ostream &ouput,Complex &c)
{
	ouput << "(" << c.real;
	if(c.imag >= 0)ouput << "+";
	ouput << c.imag << "i)" << endl;
	return ouput;
}

istream& operator >> (istream &input, Complex &c)
{
	char c1;
	cout << "input real part and imaginary part of complex number:";
	input >> c.real >> c.imag >> c1;
	return input;
}

Complex operator + (Complex c1, Complex c2)
{return Complex(c1.real + c2.real, c1.imag + c2.imag);}

Complex operator - (Complex c1, Complex c2)
{return Complex(c1.real - c2.real, c1.imag - c2.imag);}

Complex operator - (Complex &c)
{ return Complex(-c.real, -c.imag);}

Complex operator * (Complex c1, Complex c2)
{return Complex(c1.real * c2.real - c1.imag * c2.imag, c1.imag * c2.real + c1.real * c2.imag);}

Complex operator / (Complex c1, Complex c2)
{return Complex((c1.real * c2.real + c1.imag * c2.imag) / (c2.real * c2.real + c2.imag * c2.imag), (c1.imag * c2.real - c1.real * c2.imag) / (c2.real * c2.real + c2.imag * c2.imag));}

int main()
{
	double d = 2.5;
	Complex c1, c2, c3,c4;
	cin >> c1;
	cout << "请再输入一个复数：" << endl;
	cin >> c2;

	cout << "c1 = " << c1;
	cout << "c2 = " << c2;

	c3 = c1 + c2;
	cout << "c1 + c2 = " << c3;

	c3 = c1 + d;
	cout << "c1 + " << d << "= " << c3;

	c3 = Complex(d) + c1;
	cout << d << " + c1" << "= " << c3;

	c3 = c1 - c2;
	cout << "c1 - c2 = " << c3;

	c3 = c1 - d;
	cout << "c1 - " << d << "= " << c3;

	c3 = d - c1;
	cout << d << " - c1" << "= " << c3;

	c3 = c1 * c2;
	cout << "c1 * c2 = " << c3;

	c3 = c1 * d;
	cout << "c1 * " << d << "= " << c3;

    c3 = d * c1;
	cout << d << " * c1" << "= " << c3;

	c3 = c1 / c2;
	cout << "c1 / c2 = " << c3;

	c3 = c1 / d;
	cout << "c1 / " << d << "= " << c3;

	c3 = d / c1;
	cout << d << " / c1" << "= " << c3;

	c3 = - c1;
	cout << " -c1= " << c3;

	system("pause");
	return 0;
}

运行结果：