题目:求并查集集合的个数。
分析:并查集。
#include <stdio.h> #include <stdlib.h> //union_set_begin int sets[ 50001 ]; int rank[ 50001 ]; void union_set( int n ) { for ( int i = 0 ; i <= n ; ++ i ) { rank[i] = 0; sets[i] = i; } } int Find( int a ) { if ( a != sets[a] ) sets[a] = Find( sets[a] ); return sets[a]; } int Union( int a, int b ) { if ( rank[a] > rank[b] ) sets[b] = a; else { sets[a] = b; if ( rank[a] == rank[b] ) rank[b] ++; } } //union_set_end int main() { int T = 1,N,M,x,y,a,b; while ( scanf("%d%d",&N,&M) && N+M ) { union_set( N ); for ( int i = 1 ; i <= M ; ++ i ) { scanf("%d%d",&x,&y); a = Find( x ); b = Find( y ); if ( a != b ) Union( a, b ); } int count = 0; for ( int i = 1 ; i <= N ; ++ i ) if ( sets[i] == i ) ++ count; printf("Case %d: %d\n",T ++,count); } return 0; }