学步园

一：先看代码  vim 14.c

#include <iostream>

using namespace std;

void fun1 (int r)

{

cout<<"r = "<<r <<endl;

cout<<"&r= "<<&r<<endl;

r++;

cout<<"r = "<<r <<endl;

}

void fun2 (int& r)

{

cout<<"r = "<<r <<endl;

cout<<"&r= "<<&r<<endl;

r++;

cout<<"r = "<<r <<endl;

}

int main()

{

int x =0;

int y =0;

cout<<" 输出调用无引用参数传递的函数fun1的结果"<<endl ;

cout<<" 调用fun1前x和其地址"<<endl;

cout<<"x = "<<x <<endl;

cout<<"&x= "<<&x<<endl;

cout<<" 调用fun1后"<<endl;

fun1(x);

cout<<"x = "<<x <<endl;

cout<<" 输出调用引用传递参数的函数fun2的结果:"<<endl;

cout<<" 调用fun2前y和其地址"<<endl;

cout<<"y = "<<y <<endl;

cout<<"&y= "<<&y<<endl;

cout<<" 调用fun2后"<<endl;

fun2(y);

cout<<"y = "<<y <<endl;

return 0;

}