首先通过实例来分析数组
是怎么样访问
的
arr=[3,4,5,6,7,8,9]
for i in 1..3
print arr[i], "数组内容： ","/n"
end
puts arr[0]
#3
puts arr.first
#3
puts arr[arr.length-1
] #9
puts arr[arr.size-1
] #9
puts arr.last
#9
puts arr[-1]
#9
puts arr[-2] #8
print arr[1..3]
,"/n" #456
print arr[-3,2]
,"/n" #78
#数组的索引从0开始，一直到数组的长度减去
#负数表示从数组末尾开始的索引；用一对数字来索引数组
#第一个数字表示开始位置
，第二数字表示从开始位置起的元素数目
。
其次， 数组的增加
、删除
运算
arr=[4,5,6]
print arr.join(", ")
,"/n" #4, 5, 6
arr[4] = "m" #把4号索引位置元素赋值为"m"
print arr.join(", "),"/n" #4, 5, 6, , m
print arr[3] ,"/n" #打印3号索引位置元素， 3号元素为空 #nil
arr.delete_at(3) #删除3号索引位置元素
print arr.join(", "),"/n" #4, 5, 6, m
arr[2] = ["a","b","c"] #把2号索引位置元素赋值为["a","b","c"]
print arr.join(", "),"/n" #4, 5, a, b, c, m
print arr[2] ,"/n" #打印2号索引位置元素 #abc
arr[0..1] = [7,"h","b"] #把0..1号元素替换为7,"h","b"
arr.push("b" ) #加入元素"b"
print arr.join(", "),"/n" #7, h, b, a, b, c, m, b
arr.delete(["a","b","c"] )
#删除元素["a","b","c"]
print arr.join(", "),"/n" #7, h, b, m, b
arr.delete("b")
#删除所有元素"b"
print arr.join(", "),"/n" #7, h, m
arr.insert(3,"d")
#在3号索引位置插入元素"d"
print arr.join(", "),"/n" #7, h, m, d
arr<<"f"<<2 #加入元素"f"；加入元素2
print arr.join(", "),"/n" #7, h, m, d, f, 2
arr.pop
#删除尾元素
print arr.join(", "),"/n" #7, h, m, d, f
arr.shift
#删除首元素
print arr.join(", "),"/n" #h, m, d, f
arr.clear
#清空数组arr
print arr.join(", "),"/n" #
print arr.length
=end
最后，数组的运算
aaaa=[" wa ",4,5," bb "]
bbbb=[4,1,3,2,5," was "," wa "]
ccc = [4,1,3,2,5]
print aaaa + bbbb ,"/n" # wa 45 bb 41325 was wa 加运算
print bbbb+ aaaa ,"/n" #41325 was wa wa 45 bb
print aaaa * 2 ,"/n" # wa 45 bb wa 45 bb 乘运算
print "减法运算、",bbbb - aaaa ,"/n" #132 was 减运算
， 这里区分空格
#并运算；交运算
print aaaa | bbbb ,"/n" # wa 45 bb 132 was 并运算
print aaaa & bbbb ,"/n" # wa 45 交运算
#排序；倒置
print ccc.sort ,"/n" #12345
print aaaa.reverse ,"/n" # bb 54 wa