关于Window.ShowDialog()方法,有一个常见的容易犯的错误。下面给出这个错误的例子:
DemoA:错误的例子
1. 在WPF项目中,创建一个Windows:DialogWindow
DialogWindow.xaml
<Window x:Class="DemoA.DialogWindow" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Title="I am a dialog window" Height="200" Width="300"> <Grid> <Grid.RowDefinitions> <RowDefinition Height="140" /> <RowDefinition Height="60" /> </Grid.RowDefinitions> <Label Grid.Row="0" Margin="12" Content="Hello!" /> <WrapPanel Grid.Row="1" Margin="0" HorizontalAlignment="Center"> <Button Content="OK" Margin="5,0,5,0" Width="60" /> <Button Content="Cancel" Margin="5,0,5,0" Width="60" Click="ButtonCancelOnClick"/> </WrapPanel> </Grid> </Window>
DialogWindow.xaml.cs
using System.Windows; namespace DemoA { /// <summary> /// Interaction logic for DialogWindow.xaml /// </summary> public partial class DialogWindow : Window { public DialogWindow() { InitializeComponent(); } private void ButtonCancelOnClick(object sender, RoutedEventArgs e) { this.Close(); } } }
然后在MainWindow里面去调用它:
MainWindow.xaml
<Window x:Class="DemoA.MainWindow" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Title="MainWindow" Height="350" Width="525"> <Grid> <Button Width="Auto" Height="Auto" Content="Show dialog" Click="ButtonClick" /> </Grid> </Window>
MainWindow.xaml.cs
using System.Windows; namespace DemoA { /// <summary> /// Interaction logic for MainWindow.xaml /// </summary> public partial class MainWindow : Window { private DialogWindow dialogWindow = new DialogWindow(); public MainWindow() { this.InitializeComponent(); } private void ButtonClick(object sender, RoutedEventArgs e) { dialogWindow.ShowDialog(); } } }
这个例子似乎非常寻常。看出它有什么问题了吗?如果您看出问题来了,那么本文对您来说纯属浪费时间,请移步其它文章,谢谢。
好,下面我们运行它。运行时,点击MainWindow窗口的按钮,第一次点击,弹出了DialogWindow对话框,没什么问题。点击“Cancel”按钮关闭DialogWindow对话框,再次点击MainWindow窗口的按钮,这时候问题出现了,抛出了以下异常:
An unhandled exception of type 'System.InvalidOperationException' occurred in PresentationFramework.dll Additional information: Cannot set Visibility or call Show, ShowDialog, or WindowInteropHelper.EnsureHandle after a Window has closed.
如何解决这个问题呢?解决方案如下:DemoB
DialogWindow.xaml.cs
using System.Windows; namespace DemoB { /// <summary> /// Interaction logic for DialogWindow.xaml /// </summary> public partial class DialogWindow : Window { private static DialogWindow staticInstance = null; public DialogWindow() { this.InitializeComponent(); this.Closed += WindowOnClosed; } public static DialogWindow GetInstance() { if (staticInstance == null) { staticInstance = new DialogWindow(); } return staticInstance; } private void ButtonCancelOnClick(object sender, RoutedEventArgs e) { this.Close(); } private void WindowOnClosed(object sender, System.EventArgs e) { staticInstance = null; } } }
MainWindow.xaml.cs
using System.Windows; namespace DemoB { /// <summary> /// Interaction logic for MainWindow.xaml /// </summary> public partial class MainWindow : Window { public MainWindow() { this.InitializeComponent(); } private void ButtonClick(object sender, RoutedEventArgs e) { DialogWindow.GetInstance().ShowDialog(); } } }
这样,每次调用Window.ShowDialog()方法的时候,都创建了一个新的DialogWindow实例,所以问题得以解决。
参考:
同样的疑问,在StackOverflow上的讨论如下:
《WPF: Cannot reuse window after it has been closed》
http://stackoverflow.com/questions/3568233/wpf-cannot-reuse-window-after-it-has-been-closed