学步园

1、首先下载 urlrewritefilter-2.6

2、新建一个 Java Web工程

3、添加 urlrewrite-2.6.0.jar 到 lib 并在 WEB-INF 新建 urlrewrite.xml 文件

<?xml version="1.0" encoding="utf-8"?><br /> <!DOCTYPE urlrewrite PUBLIC "-//tuckey.org//DTD UrlRewrite 2.6//EN"<br /> "http://tuckey.org/res/dtds/urlrewrite2.6.dtd"></p> <p><urlrewrite><br /> <rule></p> <p> <from>/([0-9]+)_([0-9]+).html</from><br /> <to type="forward">/UrlRewriterServlet?id=$1&id2=$2</to><br /> </rule><br /> </urlrewrite><br />

4、 在 web.xml 文件中配置

<filter><br /> <filter-name>UrlRewriteFilter</filter-name><br /> <filter-class>org.tuckey.web.filters.urlrewrite.UrlRewriteFilter</filter-class><br /> </filter><br /> <filter-mapping><br /> <filter-name>UrlRewriteFilter</filter-name><br /> <url-pattern>/*</url-pattern><br /> </filter-mapping>

5、 新建一个Servlet ：UrlRewriterServlet

      package com.urlrewriter.servlet;</p> <p>import java.io.IOException;</p> <p>import javax.servlet.ServletException;<br /> import javax.servlet.http.HttpServlet;<br /> import javax.servlet.http.HttpServletRequest;<br /> import javax.servlet.http.HttpServletResponse;</p> <p>@SuppressWarnings("serial")<br /> public class UrlRewriterServlet extends HttpServlet {</p> <p> public void doGet(HttpServletRequest request, HttpServletResponse response)<br /> throws ServletException, IOException {</p> <p> this.doPost(request, response);<br /> }</p> <p> public void doPost(HttpServletRequest request, HttpServletResponse response)<br /> throws ServletException, IOException {</p> <p> String id = request.getParameter("id");<br /> String id2 = request.getParameter("id2");</p> <p> System.out.println("id is " + id);</p> <p> System.out.println("id2 is " + id2);</p> <p> //response.sendRedirect("index.jsp");</p> <p> }</p> <p>}<br />

6、在地址栏中输入 http://localhost:8080/URLRewriter/1_2.html,

    后台输出

    id is  1
    id2 is  2