package com.gc.action;   
  
import java.io.IOException;   
import java.util.HashMap;   
import java.util.Map;   
  
import javax.servlet.ServletException;   
import javax.servlet.http.HttpServletRequest;   
import javax.servlet.http.HttpServletResponse;   
  
//import org.apache.log4j.Logger;   
import org.springframework.web.servlet.ModelAndView;   
import org.springframework.web.servlet.mvc.Controller;   
  
public class HelloWorldAction implements Controller {   
  //private Logger logger = Logger.getLogger(this.getClass().getName());   
  
  private String helloWorld;   
  
  private String viewPage;   
  
  // 实现 Controller 接口中的 handleRequest() 方法   
  public ModelAndView handleRequest(HttpServletRequest req,   
      HttpServletResponse res) throws ServletException,IOException {   
    Map<STRING,STRING> model = new HashMap<STRING,STRING>();   
    model.put("helloWorld",getHelloWorld());   
    return new ModelAndView(getViewPage(),model);   
  }   
  
  public String getHelloWorld() {   
    return helloWorld;   
  }   
  
  public void setHelloWorld(String helloWorld) {   
    this.helloWorld = helloWorld;   
  }   
  
  public String getViewPage() {   
    return viewPage;   
  }   
  
  public void setViewPage(String viewPage) {   
    this.viewPage = viewPage;   
  }   
  
} <PRE></PRE>

  
  
helloWorldActionorg.springframework.web.servlet.view.InternalResourceViewHelloWorld/WEB-INF/JSP/index.jsp


 
<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>  
  
  
    
      
    
 <%   
String str = (String)request.getAttribute("helloWorld");   
%>  
    
    
<%=str%>
  
    


 
dispatcherServletorg.springframework.web.servlet.DispatcherServletcontextConfigLocation/WEB-INF/dispatcherServlet-servlet.xml1dispatcherServlet*.do


书上的实例完全是在有ｔｏｍｃａｔ插件的情况下写的，而我呢，偏偏没有安装插件，我感觉应该可以的，结果却是令人失望的，搞了一天也没头绪，就连ｔｏｍｃａｔ可能也要重装了，逆天而行真的不行吗？我还要试试……