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poj2503Babelfish(Trie tree 或者map)

2013年03月10日 ⁄ 综合 ⁄ 共 2072字 ⁄ 字号 评论关闭

->题目还是戳这里<-

题目大意:还是给你一个字典,翻译单词。

题目分析:题目蛮简单,字典树练手题。不过STL可以水过。输入有点小刁难,需要小心点,其他的就没什么了。

详情请见代码:

#include <iostream>
#include<cstdio>
#include<cstring>
#include<string>
#include<cstdlib>
#include<map>
using namespace std;
const int N = 1000005;

map<string,string> lcm;
char explan[20],s[20];

int input()
{
    int i = 0;
    int flag = 0;
    char c;
    while(c = getchar())
    {
        if(c == '\n')
        {
            if(i == 0)
                return 0;
            else
            {
                s[i] = '\0';
                return 1;
            }
        }
        else
        {
            if(c == ' ')
            {
                explan[i] = '\0';
                i = 0;
                flag = 1;
            }
            else
            {
                if(flag)
                    s[i ++] = c;
                else
                    explan[i ++] = c;
            }
        }
    }
}


int main()
{
    while(input())
    {
        lcm[s] = explan;
    }
    while(scanf("%s",s) != EOF)
    {
        map<string,string>::iterator it = lcm.find(s);
        if(it != lcm.end())
            cout<<lcm[s]<<endl;//printf("%s\n",lcm[s]);
        else
            printf("eh\n");
    }
    return 0;
}
//9632K	1157MS

/*
typedef struct node
{
    struct node * next[26];
    char s[101];
    int end;
}tree;
char s[101];
char explan[101];

int input()
{
    int i = 0;
    int flag = 0;
    char c;
    while(c = getchar())
    {
        if(c == '\n')
        {
            if(i == 0)
                return 0;
            else
            {
                s[i] = '\0';
                return 1;
            }
        }
        else
        {
            if(c == ' ')
            {
                explan[i] = '\0';
                i = 0;
                flag = 1;
            }
            else
            {
                if(flag)
                    s[i ++] = c;
                else
                    explan[i ++] = c;
            }
        }
    }
}

void init(tree *t)
{
    memset(t->s,0,sizeof(t->s));
    for(int i = 0;i < 26;i ++)
        t->next[i] = NULL;
    t->end = 0;
}

void build(tree *t,int id)
{
    if(t->next[s[id] - 'a'] == NULL)
    {
        t->next[s[id] - 'a'] = (tree *)malloc(sizeof(tree));
        init(t->next[s[id] - 'a']);
    }
    if(s[id + 1] == '\0')
    {
        strcpy(t->next[s[id] - 'a']->s,explan);
        t->next[s[id] - 'a']->end = 1;
        return;
    }
    else
    {
        build(t->next[s[id] - 'a'],id + 1);
    }
}

void query(tree *t,int id)
{
    if(s[id] != '\0' && t->next[s[id] - 'a'] == NULL)
    {
        printf("eh\n");
        return;
    }
    if(s[id] == '\0')
    {
        if(t->end == 1)
        {
            //printf("%s\n",t->s);
            int i = 0;
            while(t->s[i])
            {
                putchar(t->s[i]);
                i ++;
            }
            putchar('\n');
            return;
        }
        else
        {
            printf("eh\n");
            return;
        }
    }
    else
        query(t->next[s[id] - 'a'],id + 1);
}

void print(tree *t)
{
    for(int i = 0;i < 26;i ++)
    {
        if(t->next[i] != NULL)
            print(t->next[i]);
    }
    if(t->end)
    {
        printf("%s\n",t->s);
        return;
    }
}

int main()
{
    tree *root = NULL;
    root = (tree *)malloc(sizeof(tree));
    init(root);
    while(input())
    {
        build(root,0);
        //printf("%s %s\n",explan,s);
    }
    //print(root);
    //system("pause");
    while(scanf("%s",s) != EOF)
    {
        s[strlen(s)] = '\0';
        query(root,0);
    }
    return 0;
}*/
//27976K	735MS
/*
dog ogday
cat atcay
pig igpay
froot ootfray
loops oopslay
s ab
sb abs
sba absd

atcay
ittenkay
oopslay
a
ab
abs
absd
absda

ab sb
aba sba

s
sb
sba
*/

交了2份代码,效率差别很大,如果静态字典树,效率会更高。

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