学步园

Everyone making translations from English to Russian knows an English phrase "Naked conductor runs along the bus". It has two very different meanings.

Every bus in the Ekaterinburg city has a special man (or woman) called conductor. When you ride the bus, you have to give money to the conductor. We know that there are more than
P% conductors and less than Q% conductors of all citizens of Ekaterinburg. Your task is to determine a minimal possible number of Ekaterinburg citizens. By percentage, we know that there are more than P% conductors and less than Q% conductors
of all Russian citizens in this city

Two numbers P,Q such that 0.01 ≤
P, Q ≤ 99.99. Numbers are given with 2 digits precision. These numbers are separated by some spaces or "end of line" symbols.

The minimal number of Ekaterinburg citizens.

If there are 15 citizens and 2 conductors among them in Ekaterinburg, then there are 13 1/3 % conductors of all citizens.

 

给出售票员占全市人口的百分比的上限与下限，求出全市人口的最小数目，要注意不能包括上限与下限，还有精度。。。

 

#include <iostream>
#include <stdio.h>
#include <string.h>
#include <math.h>
#include <algorithm>
using namespace std;
double p,q,l,r;
int L,R,ans;

int main()
{
    while(cin>>p>>q)
    {
        ans = 1;
        while(1)
        {
            l = ans*p/100.0;
            r = ans*q/100.0;
            L = (int)l;
            R = (int)r;
            if(R>L && fabs(l-L)>1e-6 && fabs(r-R)>1e-6)
            {
                cout<<ans<<endl;
                break;
            }
            ans++;
        }
    }

    return 0;
}