当我们请求一个经过权限控制的请求不通过时，会跳转到一个地方请求权限，请求结束后需要跳转回之前的页面。比如我们请求一个需要登录的action，会被跳转到login页面，我们希望登录成功后跳转到我们之前希望去的action页面。要实现这个，只需要在login之后，执行以下这句即可：
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Yii:app()->getRequest()-redirect(Yii::app()->user->getReturnUrl()); |
为什么呢？因为在请求一个需要登录的aciton的跳转到登录页面之前，yii会把当前请求的url存到user对象的returnUrl属性中，方便后面的跳转。有代码为证（来自Yii源码）：
//先遭到CAccessControllFilter拦截，执行它的accessDenied方法
/**
* Denies the access of the user.
* This method is invoked when access check fails.
* @param IWebUser $user the current user
* @param string $message the error message to be displayed
*/
protected function accessDenied($user,$message)
{
if($user->getIsGuest())
$user->loginRequired();
else
throw new CHttpException(403,$message);
}
//然后执行CWebUser中的loginRequired方法
/**
* Redirects the user browser to the login page.
* Before the redirection, the current URL (if it's not an AJAX url) will be
* kept in {@link returnUrl} so that the user browser may be redirected back
* to the current page after successful login. Make sure you set {@link loginUrl}
* so that the user browser can be redirected to the specified login URL after
* calling this method.
* After calling this method, the current request processing will be terminated.
*/
public function loginRequired()
{
$app=Yii::app();
$request=$app->getRequest();
if(!$request->getIsAjaxRequest())
$this->setReturnUrl($request->getUrl());
elseif(isset($this->loginRequiredAjaxResponse))
{
echo $this->loginRequiredAjaxResponse;
Yii::app()->end();
}
if(($url=$this->loginUrl)!==null)
{
if(is_array($url))
{
$route=isset($url[0]) ? $url[0] : $app->defaultController;
$url=$app->createUrl($route,array_splice($url,1));
}
$request->redirect($url);
}
else
throw new CHttpException(403,Yii::t('yii','Login Required'));
}