学步园

Given a matrix of m x n elements
(m rows, n columns),
return all elements of the matrix in spiral order.

For example,

Given the following matrix:

[
 [ 1, 2, 3 ],
 [ 4, 5, 6 ],
 [ 7, 8, 9 ]
]

You should return [1,2,3,6,9,8,7,4,5].

void printacircle(vector<vector<int> > &matrix, vector<int> &path, int num)
    {
    	int row = matrix.size();
		int col = matrix[0].size();

		for(int i = num; i < col-num; i++)
			path.push_back(matrix[num][i]);
		if( 2*num+2 <= row)
			for(int i = num+1; i < row-num; i++)
				path.push_back(matrix[i][col-num-1]);
		if(2*num+2<= col && 2*num+2 <= row)
			for(int i = col-2-num; i >= num; i--)
				path.push_back(matrix[row-1-num][i]);
		if( 2*num+3 <= row && 2*num+2 <= col)
			for(int i = row-2-num; i >= num+1; i--)
				path.push_back(matrix[i][num]);
	}
	vector<int> spiralOrder(vector<vector<int> > &matrix) {
        // Start typing your C/C++ solution below
        // DO NOT write int main() function
        vector<int> path;
        int row = matrix.size();
        if(row<1)return path;
        int col = matrix[0].size();
		
		for(int i = 0; i< (row+1)/2 && i < (col+1)/2; ++i)
			printacircle(matrix, path, i);
    }