现在的位置: 首页 > 综合 > 正文

编程实现单链表的逆置

2014年10月04日 ⁄ 综合 ⁄ 共 899字 ⁄ 字号 评论关闭
#include <tchar.h>
#include <iostream>
using namespace std;

typedef struct student{
	int data;
	struct student * next; 
} node;

node* create()
{
	node *head, *p, *s;
	int x, cycle = 1;
	head = (node *)malloc(sizeof(node));
	p = head;
	while(cycle)
	{
		cout << "please input the data: ";
		cin >> x;
		cout << endl;
		if( x != 0)
		{
			s = (node *)malloc(sizeof(node));
			s->data = x;
			p->next = s;
			p = s;
		}
		else
		{
			cycle = 0;
		}
		
	}
	p->next = NULL;
	head = head->next;
	return head;
}

int length(node *head)
{
	int n = 0;
	node *p;
	p = head;
	while (p != NULL)
	{
		p = p->next;
		n++;
	}
	return n;
}

void print(node *head)
{
	int n;
	node *p;
	p = head;
	n = length(head);
	cout << "There is " << n << " data in list\n" << endl;
	while(p != NULL)
	{
		cout << p->data << " -> ";
		p = p->next;
	}
	cout << endl;
}

node *reverse(node *head)
{
	node *p1, *p2, *p3;
	if(NULL == head && NULL == head->next)
		return head;
	p1 = head;
	p2 = p1->next;
	while(p2)
	{
		p3 = p2->next;
		p2->next = p1;
		p1 = p2;
		p2 = p3;
	}
	head->next = NULL;
	head = p1;
	return head;
}

int _tmain(int argc, _TCHAR * argv[])
{
	node *head;
	head = create();
	print(head);
	head = reverse(head);
	print(head);
	return 0;
}

抱歉!评论已关闭.