Binomial Showdown
Time Limit: 1000MS | Memory Limit: 65536K | |
Total Submissions: 18358 | Accepted: 5600 |
Description
In how many ways can you choose k elements out of n elements, not taking order into account?
Write a program to compute this number.
Write a program to compute this number.
Input
The input will contain one or more test cases.
Each test case consists of one line containing two integers n (n>=1) and k (0<=k<=n).
Input is terminated by two zeroes for n and k.
Each test case consists of one line containing two integers n (n>=1) and k (0<=k<=n).
Input is terminated by two zeroes for n and k.
Output
For each test case, print one line containing the required number. This number will always fit into an integer, i.e. it will be less than 231.
Warning: Don't underestimate the problem. The result will fit into an integer - but if all intermediate results arising during the computation will also fit into an integer depends on your algorithm. The test cases will go to the limit.
Warning: Don't underestimate the problem. The result will fit into an integer - but if all intermediate results arising during the computation will also fit into an integer depends on your algorithm. The test cases will go to the limit.
Sample Input
4 2 10 5 49 6 0 0
Sample Output
6 252 13983816
Source
ac代码
#include<stdio.h> #include<string.h> __int64 c(int a,int b) { __int64 ans=1; int i; if(b>a/2) b=a-b; for(i=1;i<=b;i++) { ans*=(a-i+1); ans/=i; } return ans; } int main() { int a,b; while(scanf("%d%d",&a,&b)!=EOF,a||b) { printf("%I64d\n",c(a,b)); } }