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HEU 2013 Advanced Fruits

2012年05月27日 ⁄ 综合 ⁄ 共 1764字 ⁄ 字号 评论关闭
/**************************************
Problem: HEU 2013 Advanced Fruits
Time: 0.0020 s
Memory: 548 k 
Accepted Time: 2009-05-08 18:49:38
Tips: 求最大公共子序列,考虑最大值为0时的特殊情况 
*************************************
*/

#include 
<stdio.h>
#include 
<string.h>
int main()
{
    
char a[109],b[109];
    
int table[109][109];
    
int aa[109],bb[109];
    
while(scanf("%s%s",a+1,b+1)!=EOF)
    
{
        
int i,j;
        
int lena=strlen(a+1),lenb=strlen(b+1);
        
for(i=0;i<=lena;i++)table[0][i]=0;
        
for(i=0;i<=lenb;i++)table[i][0]=0;
        
for(i=1;i<=lena;i++)
        
{
            
for(j=1;j<=lenb;j++)
            
{
                
if(a[i]==b[j])table[i][j]=table[i-1][j-1]+1;
                
else if(table[i-1][j]>table[i][j-1])table[i][j]=table[i-1][j];
                
else table[i][j]=table[i][j-1];
            }

        }

        
if(table[lena][lenb]==0)printf("%s%s\n",a+1,b+1);
        
else
        
{
            
int ii=0,jj;
            i
=lena,j=lenb;
            
while(i!=0&&j!=0)
            
{
                
if(table[i][j]==table[i-1][j-1]+1&&a[i]==b[j])
                
{
                    aa[ii]
=i;
                    bb[ii]
=j;
                    ii
++;
                    i
--,j--;
                }

                
else if(table[i-1][j]>table[i][j-1])i--;
                
else j--;
            }

            ii
=jj=1;
            
for(i=table[lena][lenb]-1;i>=0;i--)
            
{
                
while(ii!=aa[i])
                
{
                    printf(
"%c",a[ii]);
                    ii
++;
                }

                
while(jj!=bb[i])
                
{
                    printf(
"%c",b[jj]);
                    jj
++;
                }

                printf(
"%c",a[ii]);
                ii
++,jj++;
            }

            printf(
"%s%s\n",a+aa[0]+1,b+bb[0]+1);
        }

    }

    
return 0;
}

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