MiYu原创, 转帖请注明 : 转载自 ______________白白の屋
题目地址: http://acm.hdu.edu.cn/showproblem.php?pid=1063
题目描述:
Exponentiation
Time Limit: 1000/500 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 1696 Accepted Submission(s): 376
This problem requires that you write a program to compute the exact value of Rn where R is a real number ( 0.0 < R < 99.999 ) and n is an integer such that 0 < n <= 25.
95.123 12 0.4321 20 5.1234 15 6.7592 9 98.999 10 1.0100 12
548815620517731830194541.899025343415715973535967221869852721 .00000005148554641076956121994511276767154838481760200726351203835429763013462401 43992025569.928573701266488041146654993318703707511666295476720493953024 29448126.764121021618164430206909037173276672 90429072743629540498.107596019456651774561044010001 1.126825030131969720661201
这两天突然想学习下JAVA 的大数 就学习了一下, 这道题在PKU A掉了的, 不过在 HDU 一直没过, 不知道有什么恶心的数据把我给恶心掉了, 很郁闷.
不过 用JAVA直接 1 A 了........... 很简单的说
代码如下 :
/*
* To change this template, choose Tools | Templates
* and open the template in the editor.
*/
import java.util.Scanner;
import java.math.*;
/**
*
* @author baiyun
*/
public class Main {
/**
* @param args the command line arguments
*/
public static void main(String[] args) {
Scanner in = new Scanner ( System.in );
BigDecimal num;
int exp;
while ( in.hasNext() ){
num = in.nextBigDecimal();
exp = in.nextInt();
num = num.pow ( exp );
num = num.stripTrailingZeros();
String out = num.toPlainString();
if ( out.charAt(0) == '0' )
out = out.substring(1);
System.out.println( out );
}
}
}