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翻转有序链表的部分节点(美团)

2016年08月24日 ⁄ 综合 ⁄ 共 1248字 ⁄ 字号 评论关闭

相对于翻转整个链表而言,主要是对head指针的初始化改为对应节点的next,及翻转的while判断对应到指定节点即可。

/*************************************************************
 reverse_list.c
 auther:yejing
 data:2014/10/21 creat file   1.0
      2015/01/04 modified for partition reverse of a list 1.1
*************************************************************/
#include <stdio.h>
#include <stdlib.h>

typedef struct node_s{
	int item;
	struct node_s* next;
}node_t;

void show_list(node_t* list);

node_t* search_for_key_pointer(int n, node_t* head){
	node_t* tmp = head;
	while(tmp){
		if(n == tmp->item)
			return tmp;
		tmp = tmp->next;
	}

	return NULL;
}

node_t* reverse_part_of_list(node_t* head, int index){
	if(!head)
		return;
		
	node_t* n = head;
	head = search_for_key_pointer(index, head)->next;
	while(n && n->item <= index){
		node_t* m = n;
		n = n->next;
		m->next = head;
		head = m;
	}
	printf("  -----reverseing list-----\n");
	return head;
}

node_t* creat(int n)
{
	node_t* phead = (node_t*)malloc(sizeof(node_t));
	if(!phead)
		return NULL;
		
	int i;
	node_t *p, *q;
	p = phead;
	phead->item = 1;
	for(i = 0; i < n - 1; ++i)
	{
		q = (node_t *)malloc(sizeof(node_t));
		if(!q)
			return;
		p->next = q;
		q->item = i + 2;
		p = q;
	}
	return phead;
}

void show_list(node_t* list)
{
	if(!list)
		return;
	while(list){
		printf(" item of listnode is: %d \n", list->item);
		list = list->next;
	}
	return;
}

int main(int argc, char* argv[])
{
	node_t* list = creat(5);
	show_list(list);
	list = reverse_part_of_list(list, 4);
	show_list(list);
	return 1;
}

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