一个简单的Struts2.0小例子
-----------First Struts2.0 Project------------
1.建立一个web Project;
2.导入struts2.0的核心包,注意全部导入全部的lib会引起错误；
commons-fileupload-1.2.1.jar
commons-io-1.3.2.jar
freemarker-2.3.12.jar
ognl-2.6.11.jar
struts2-core-2.1.2.jar
xwork-2.1.1.jar
3.工程配置
3.1 struts.xml
把配置文件放在src的根目录下，在struts2.0中默认的配置文件不再是struts-default.xml，而是struts.xml
配置文件内容是：
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE struts PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 2.0//EN"
"http://struts.apache.org/dtds/struts-2.0.dtd">
<struts>
<include file="struts-default.xml"></include>
<package name="com" extends="struts-default">
<action name="Hello" class="com.Hello">
<result>/hello.jsp</result>
</action>
</package>
</struts>
--其中<package name="com"中的name可以调整；
<action name="Hello" class="com.Hello"> //代表Action的名称和实际存放位置
<result>/hello.jsp</result> //表示导向页面
3.2 web.xml中必须说明filter和filter-mapping的内容
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<filter>
<filter-name>struts</filter-name>
<filter-class>org.apache.struts2.dispatcher.FilterDispatcher</filter-class>
</filter>
<filter-mapping>
<filter-name>struts</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
3.3 Action在Struts2.0种已经把ActionForm和Action合二为一；
package com;
import com.opensymphony.xwork2.ActionSupport;
@SuppressWarnings("serial")
public class Hello extends ActionSupport {
private String message;
public String getMessage() {
return message;
}
public void setMessage(String message) {
this.message = message;
}
public String execute(){
message = message + ",Hello";
return SUCCESS;
}
}
3.4 index.jsp 起始页面
<%@ page language="java" import="java.util.*" pageEncoding="ISO-8859-1"%>
<%@ taglib prefix="s" uri="/struts-tags" %>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<base href="<%=basePath%>">
<title>My JSP 'index.jsp' starting page</title>
<meta http-equiv="pragma" content="no-cache">
<meta http-equiv="cache-control" content="no-cache">
<meta http-equiv="expires" content="0">
<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
<meta http-equiv="description" content="This is my page">
<!--
<link rel="stylesheet" type="text/css" href="styles.css">
-->
</head>
<body>
This is my first project. <br>
<s:form action="Hello">
Message:<s:textfield name="message"></s:textfield>
<s:submit></s:submit>
</s:form>
</body>
</html>
3.5 hello.jsp 响应页面
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<%@ taglib prefix="s" uri="/struts-tags" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<h3><s:property value="message"/> </h3><br>
<a href="index.jsp">Back</a>
</body>
</html>