学步园

成员函数指针的行为含香函数指针，但你想调用他们时，除了参数之外，你还必须传递一个对象。

class Parrot
{
public:
	void Eat()
	{
		cout << "Tsk, knick, tsk..." << endl;
	}

	void Speak()
	{
		cout << "On Captain, My Captain" << endl;
	}
};

int main()
{
	// Define a type: pointer to a member function of Parrot,taking no arguments and return void
	typedef void(Parrot::*TpMemFun) ();
        
        // Create an object of that type and initialize it  with the address of Parrot::Eat
	TpMemFun pActivity = &Parrot::Eat;
        // Create a Parrot...
	Parrot geronimo;
        // a pointer to it...
	Parrot *pGeronimo = &geronimo;
	
        // Invoke the member function stored in Activity
        // via an object. Notice the user of operator.*
	(geronimo.*pActivity)();

        // Same, via pointer. Now we use operator->*   
	(pGeronimo->*pActivity)();
	
        // Change the activity
	pActivity = &Parrot::Speak;
	(geronimo.*pActivity)();

	return 0;
}

你可以获取一般函数的 reference， 却无法获得成员函数的 reference。