Binary
Tree Level Order Traversal:
Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right,
level by level).
For example:
Given binary tree {3,9,20,#,#,15,7}
,
3 / \ 9 20 / \ 15 7
return its level order traversal as:
[ [3], [9,20], [15,7] ]
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: vector<vector<int> > levelOrder(TreeNode *root) { // Start typing your C/C++ solution below // DO NOT write int main() function vector<int> level; vector<vector<int> > ans; if ( !root ) return ans; queue<TreeNode* > Q; Q.push(root); int lsum=1; while(lsum>0) { int next=0; level.clear(); while(lsum--) { TreeNode* tmp=Q.front(); Q.pop(); level.push_back(tmp->val); if ( tmp->left ) { Q.push(tmp->left); next++; } if ( tmp->right) { Q.push(tmp->right); next++; } } ans.push_back(level); lsum=next; } return ans; } };