先从中找出性能最好的那个数，
在用钱比较少的去组合，能组出来就表明答案在mid的右边，反之在左边，
#include<string.h>
#include<map>
#include<stdio.h>
#include<iostream>
#include<algorithm>
using namespace std;
map<string,int> vic;//以字符映射数字
int end,start;
int num;
int m,n;
int sba,sbb;
char name[1000];
int pnum[1005];
struct node{
int v,q;
}p[1005][1005];
bool cmp(node a,node b)
{
return a.v<b.v;
}
int judge(int mid)
{
int sum=0,i,j;
for(i=1;i<num;i++)
{
for(j=0;j<pnum[i];j++)
{
if(p[i][j].q>=mid&&sum+p[i][j].v<m)
{
sum+=p[i][j].v;
break;
}
}
if(j==pnum[i])//质量高了
return 0;
}
return 1;
}
int main()
{
int t;
scanf("%d",&t);
while(t--)
{
vic.clear();//映射
scanf("%d %d\n",&n,&m);
memset(pnum,0,sizeof(pnum));
end=0;
start=0;
num=1;
for(int i=0;i<n;i++)
{
scanf("%s%*s%d%d",name,&sba,&sbb);
if(end<sbb)
end=sbb;
if(!vic[name])
{
vic[name]=num++;
p[vic[name]][pnum[vic[name]]].v=sba;
p[vic[name]][pnum[vic[name]]++].q=sbb;
}
else
{
p[vic[name]][pnum[vic[name]]].v=sba;
p[vic[name]][pnum[vic[name]]++].q=sbb;
}
}
for(int i=0;i<num;i++)
sort(p[i],p[i]+pnum[i],cmp);
int mid;
while(start<end)
{
mid=(end+start)>>1;
if(judge(mid))
{
if (start == mid)
break;
start=mid;
}
else
end=mid;
}
if(judge(mid+1))
mid++;
printf("%d\n",mid);
}
return 0;
}