int start = 0;
String numStr = null;
for (int j = 0; j < valuesStr.length() - 1; j++) {
if (Character.isDigit(valuesStr.charAt(j)) == false
&& Character.isDigit(valuesStr.charAt(j + 1)) == true) {
start = j + 1;
numStr = valuesStr.substring(start, valuesStr.length());
}
}
另外还有从其他处转载的三种方法：
1用JAVA自带的函数
- public static boolean isNumeric(String str){
- for (int i = str.length();--i>=0;){
- if (!Character.isDigit(str.charAt(i))){
- return false;
- }
- }
- return true;
- }
2用正则表达式
- public static boolean isNumeric(String str){
- Pattern pattern = Pattern.compile("[0-9]*");
- return pattern.matcher(str).matches();
- }
3用ascii码
- public static boolean isNumeric(String str){
- for(int i=str.length();--i>=0;){
- int chr=str.charAt(i);
- if(chr<48 || chr>57)
- return false;
- }
- return true;
- }