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POJ 1698 Alice’s Chance

2018年03月17日 ⁄ 综合 ⁄ 共 1841字 ⁄ 字号 评论关闭

大意不再赘述。

思路:添加一个超级源点和电影数目连边,容量为需要的时间,然后将星期拆为7个点,如果有安排的话,就连边,容量为1,然后再从每个星期的7个点连一条边去汇点,容量为1,因为一天安排一个节目,最后判断压进去的流与总的天数之间的关系即可。

不知道为什么老是TLE,难道我的Dinic有问题??

#include <iostream>
#include <cstdlib>
#include <cstdio>
#include <cstring>
#include <string>
using namespace std;

const int MAXN = 1010;
const int MAXM = 40010;
const int INF = 0x3f3f3f3f;


struct Edge
{
	int v, f;
	int next;
}edge[MAXM];

int first[MAXN], level[MAXN];
int map[MAXN][10];
int q[MAXN];
int cnt;
int n, m;
int MaxWeek, totDay;
int s, t;

void init()
{
	cnt = 0;
	MaxWeek = 0;
	totDay = 0;
	memset(first, -1, sizeof(first));
}

void read_graph(int u, int v, int f)
{
	edge[cnt].v = v, edge[cnt].f = f;
	edge[cnt].next = first[u], first[u] = cnt++;
	edge[cnt].v = u, edge[cnt].f = 0;
	edge[cnt].next = first[v], first[v] = cnt++;
}

int bfs(int s, int t)
{
	memset(level, 0, sizeof(level));
	level[s] = 1;
	int front = 0, rear = 1;
	q[front] = s;
	while(front < rear)
	{
		int x = q[front++];
		if(x == t) return 1;
		for(int e = first[x]; e != -1; e = edge[e].next)
		{
			int v = edge[e].v, f = edge[e].f;
			if(!level[v] && f)
			{
				level[v] = level[x] + 1;
				q[rear++] = v;
			}
		}
	}
	return 0;
}

int dfs(int u, int maxf, int t)
{
	if(u == t) return maxf;
	int ret = 0;
	for(int e = first[u]; e != -1; e = edge[e].next)
	{
		int v = edge[e].v, f = edge[e].f;
		if(level[v] == level[u] + 1 && f)
		{
			int Min = min(maxf-ret, f);
			f = dfs(v, Min, t);
			edge[e].f -= f;
			edge[e^1].f += f;
			ret += f;
			if(ret == maxf) return ret;
		}
	}
	return ret;
}

int Dinic(int s, int t)
{
	int ans = 0;
	while(bfs(s, t)) ans += dfs(s, INF, t);
	return ans;
}

void read_case()
{
	init();
	scanf("%d", &n);
	for(int i = 1; i <= n; i++)
	{
		for(int j = 1; j <= 9; j++)
		{
			scanf("%d", &map[i][j]);
		}
		MaxWeek = max(MaxWeek, map[i][9]);
		totDay += map[i][8];
	}
}

void build()
{
	s = 0, t = n + 7*MaxWeek + 1;
	for(int i = 1; i <= n; i++)
	{
		read_graph(s, i, map[i][8]);
		for(int j = 1; j <= map[i][9]; j++)
		{
			for(int k = 1; k <= 7; k++) if(map[i][k])
			{
				read_graph(i, n+(j-1)*7+k, 1);
			}
		}
	}
	for(int i = 1; i <= MaxWeek; i++)
	{
		for(int j = 1; j <= 7; j++)
		{
			read_graph(n+(i-1)*7+j, t, 1);
		}
	}
}

void solve()
{
	read_case();
	build();
	int ans = Dinic(s, t);
	if(ans >= totDay) printf("Yes\n");
	else printf("No\n");
}

int main()
{
	int T;
	scanf("%d", &T);
	while(T--)
	{
		solve();
	}
	return 0;
}

 

 

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