Length of Last Word:
Given a string s consists of upper/lower-case alphabets and empty space characters '
, return the length of last word in the string.
'
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello
,
World"
return 5
.
class Solution { public: int lengthOfLastWord(const char *s) { // Start typing your C/C++ solution below // DO NOT write int main() function if ( !s ) return 0; int len=strlen(s); int last=len-1; while(last>=0&&s[last]==' ') --last; if( last <0 ) return 0; int first=last; while(first>=0&&s[first]!=' ') --first; return last-first; } };
这个只需要一趟遍历:
class Solution { public: int lengthOfLastWord(const char *s) { // Start typing your C/C++ solution below // DO NOT write int main() function int ans=0,cur=0; for(int i=0;s[i]!='\0';i++) { if ( s[i] !=' ' ) cur++; else { if( cur!=0) ans=cur; cur=0; } } if( cur!=0) ans=cur; return ans; } };